For this case we have that by definition of properties of powers and roots, it is fulfilled that:
\sqrt [n] {a ^ m} = a ^ {\frac {m} {n}}
n
a
m
=a
n
m
So:
\sqrt [4] {9 ^ {\frac {1} {2} x}} = 9 ^ {\frac {\frac {1} {2}} {4} x} = 9 ^ {\frac {1} {8} x}
4
9
2
1
x
=9
4
2
1
x
=9
8
1
x
So, we have to:
\sqrt [4] {9 ^ {\frac {1} {2} x}} = 9 ^ {\frac {1} {8} x}
4
9
2
1
x
=9
8
1
x
Answer:
9 ^ {\frac {1} {8} x}9
8
1
x
Option B
pa heart mo na at i reat mo ko at i follow
Answer:x^6/4
Step-by-step explanation:
Simplifying the steps
Answer:
Step-by-step explanation:
The ratio of its areas is equal to
Step-by-step explanation:
we know that
If two figures are similar, then the ratio of its areas is equal to the scale factor squared
In this problem the scale factor is equal to the ratio 10:3
Let
z-------> the scale factor
so
z2=(10/3)2=100/9
Answer:
c) 12/15 = 4/5
Step-by-step explanation:
imagine we mirror the triangle up, so that Z is on top.
then you can clearly see that 6 is cos(X) times r (and r is then 7.5).
XY is sin(X)×7.5
and again, 7.5 is r (the line making the X angle).
so, the cosine ratio of X is
6 = cos(X)×7.5
cos(X) = 6/7.5 or then 12/15. or simplified 4/5.
