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3 years ago

$345.60 marked down by 20%

Mathematics

2 answers:

goldfiish [28.3K]3 years ago

7 0

Answer:$276.48

Step-by-step explanation:

If you multiply 345.60 by 80 percent, (because it’s marked down by 20%, reducing the price) you get 276.48. Hope this helps!

lilavasa [31]3 years ago

3 0

The answer would be:

~276.48 in U.S. dollars.

Have a great day!!

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Movie A took in $142.44 million on it’s first weekend. This topped the previous opening weekend revenue set by movie B by $4.14

stepladder [879]

Revenue of Movie A on first weekend = $ 142.44 million

According to the given statement, revenue of movie A was $4.14 million more than the revenue of movie B in their first weekends.

So, we can write:

Revenue of movie A = Revenue of movie B + $4.14 million

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Thus movie B take in $138.30 million on its opening weekend.

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What is 2 1/8 in improper fraction form? * I need help now!!!!!!

KengaRu [80]

Answer:

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Step-by-step explanation:

Step 1: Multiply the whole number part (2) by the denominator (8).

2 × 8 = 16

Step 2: Add the product from Step 1 (16) to the numerator (1).

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Step 3: Write that result (17) above the denominator. So,

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3 years ago

Read 2 more answers

How do i solve this question?

Andrews [41]

when it comes to checking if a function is even or odd, it boils down to changing the argument, namely x = -x, and if the resulting function is the same as the original, then is even, if the resulting function is the same as the original but negative, is odd, if neither, well then neither :).

anyway, that said, let's first expand it and then plug in -x,

$\bf f(x)=(x^2-8)^2\implies f(x)=(x^2-8)(x^2-8)\implies f(x)=\stackrel{FOIL}{x^4-16x^2+64}\\\\[-0.35em]~\dotfill\\\\f(-x)=(-x)^4-16(-x)^2+64\qquad \begin{cases}(-x)(-x)(-x)(-x)=x^4\\(-x)(-x)=x^2\end{cases}\\\\\\f(-x)=x^4-16x^2+64\impliedby \stackrel{\textit{same as the original}}{Even}$

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4 years ago

Define the term inflation

shtirl [24]

Answer:

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a general increase in prices and fall in the purchasing value of money.

Hope this helps

Step-by-step explanation:

3 0

3 years ago

I. In a shipment of 300 connecting rods, the mean tensile strength is found to be 45 kpsi and has a standard deviation of 5 kpsi

CaHeK987 [17]

Answer:

a) Between 39 and 40 rods can be expected to have a strength less than 39.4 kpsi.

b) 260 rods are expected to have a strength between 39.4 and 60 kpsi

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 45, \sigma = 5$

(a) Assuming a normal distribution, how many rods can be expected to have a strength less than 39.4 kpsi?

The percentage of rods with a stength less than 39.4 is the pvalue of Z when X = 39.4. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{39.4 - 45}{5}$

$Z = -1.12$

$Z = -1.12$ has a pvalue of 0.1314

13.14% of rods have a strength less than 39.4 kpsi.

Out of 300

0.1314*300 = 39.42

Between 39 and 40 rods can be expected to have a strength less than 39.4 kpsi.

(b) How many are expected to have a strength between 39.4 and 60 kpsi?

The percentage of rods with a stength in this interval is the pvalue of Z when X = 60 subtracted by the pvalue of Z when X = 39.4. So

X = 60

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{60 - 45}{5}$

$Z = 3$

$Z = 3$ has a pvalue of 0.9987

X = 39.4

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{39.4 - 45}{5}$

$Z = -1.12$

$Z = -1.12$ has a pvalue of 0.1314

0.9987 - 0.1314 = 0.8673

86.73% of the rods are expected to have a strength between 39.4 and 60 kpsi

Out of 300

0.8673*300 = 260

260 rods are expected to have a strength between 39.4 and 60 kpsi

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4 years ago