Answer:
In the given figure the point on segment PQ is twice as from P as from Q is. What is the point? Ans is (2,1).
Step-by-step explanation:
There is really no need to use any quadratics or roots.
( Consider the same problem on the plain number line first. )
How do you find the number between 2 and 5 which is twice as far from 2 as from 5?
You take their difference, which is 3. Now splitting this distance by ratio 2:1 means the first distance is two thirds, the second is one third, so we get
4=2+23(5−2)
It works completely the same with geometric points (using vector operations), just linear interpolation: Call the result R, then
R=P+23(Q−P)
so in your case we get
R=(0,−1)+23(3,3)=(2,1)
Why does this work for 2D-distances as well, even if there seem to be roots involved? Because vector length behaves linearly after all! (meaning |t⋅a⃗ |=t|a⃗ | for any positive scalar t)
Edit: We'll try to divide a distance s into parts a and b such that a is twice as long as b. So it's a=2b and we get
s=a+b=2b+b=3b
⇔b=13s⇒a=23s
Answer:
1:4
Step-by-step explanation:
4 ÷ 4 = 1
16 ÷ 4 = 4
4:16 ratio simplified is 1:4
Answer:
the answer is either mean or median because you can find both of them given the data
Answer:
sum was 300000
Step-by-step explanation:
let sum of money is placed is x rs
Term T = 3 years, rate R = 10%
Then simple interest for for 3 years is
Sum of x will become x+0.3x = 1.3x after 3 years. now this 1.3x is kept for compound interest for two years. ie
![A =P[1+R]^t\\471900=1.3x[1+\frac{10}{100} ]^2\\x=\frac{471900}{1.573} \\x=300000](https://tex.z-dn.net/?f=A%20%3DP%5B1%2BR%5D%5Et%5C%5C471900%3D1.3x%5B1%2B%5Cfrac%7B10%7D%7B100%7D%20%5D%5E2%5C%5Cx%3D%5Cfrac%7B471900%7D%7B1.573%7D%20%5C%5Cx%3D300000)
Sum was 300000
Answer:
I think A is the answer
hope this helps
have a good day :)
Step-by-step explanation:
