Two blocks with masses m1=0.25kg and m2=1.4kg approach each other along a horizontal, frictionless track. The initial velocities
1 answer:
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Answer:
V = 6.55*10^{-6} v
Explanation:
The number density can be determined by using below formula:
where,
B is uniform magnetic field 0.74
i is current 18 A
V is hall potential difference
l is thickness 150 MICRO METER
e is electron charge 1.6 *10^{-19} C
therefore V can be determined as
V = 6.55*10^{-6} v
<h2>Answer:</h2>
0.5Ω
<h2>Explanation:</h2>Since different currents are passing through the resistors, then the resistors are most probably connected in parallel. This also means that the same voltage will pass across them.
Using Ohm's law, the voltage across a resistor in a circuit is given by;
V = I(R + r) -----------(i)
<em>For the 1ohm resistor, the voltage across it is given by;</em>
<em>Where;</em>
I = current passing through the 1 ohm resistor = 0.6A
R = resistance of the 1 ohm resistor = 1Ω
r = internal resistance of the cell = r
Substitute these values into equation (i) as follows;
V = 0.6(1 + r) -------------------(ii)
<em>For the 4.0ohm resistor, the voltage across it is given by;</em>
<em>Where;</em>
I = current passing through the 4.0 ohms resistor = 0.2A
R = resistance of the 4.0 ohms resistor = 4.0Ω
r = internal resistance of the cell = r
Substitute these values into equation (i) as follows;
V = 0.2(4.0 + r) -------------------(iii)
<em>Now solve equations (ii) and (iii) simultaneously;</em>
V = 0.6(1 + r)
V = 0.2(4.0 + r)
Substitute the value of V in equation (ii) into equation (iii). Therefore, we have;
0.6(1 + r) = 0.2(4.0 + r)
<em>Solve for r</em>
0.6 + 0.6r = 0.8 + 0.2r
0.6r - 0.2r = 0.8 - 0.6
0.4r = 0.2
r =
r = 0.5
Therefore, the internal resistance of the cell is 0.5Ω
Answer:
Explanation:
As we know by first law of thermodynamics that for ideal gas system we have
Heat given = change in internal energy + Work done
so here we will have
Heat given to the system = 2.2 kJ
Q = 2200 J
also we know that work done by the system is given as
so we have