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3 years ago

15

This is because we see evidence of plate movement in the fact that as we look at rocks farther and farther from the ridge, the r

ocks--
A)Have higher iron content

B)Are made up of smaller particles

C)Become thicker and thicker

D)Are consistently older

2 answers:

Arisa [49]3 years ago

8 0

Answer:c

Explanation:

Flauer [41]3 years ago

6 0

Answer:

C

Explanation:

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Describe in short the working system of a water pump

Monica [59]

The pump is powered by an electric motor that drives an impeller, or centrifugal pump. The impeller moves water, called drive water, from the well through a narrow orifice, or jet, mounted in the housing in front of the impeller.

5 0

4 years ago

A roundabout is a type of playground equipment involving a large flat metal disk that is able to spin about its center axis. A r

Zina [86]

Answer:

116.1 kgm²/s

1.12718 rad/s

Decreases

Explanation:

m = Mass of girl = 43 kg

M = Mass of roundabout = 120 kg

v = Velocity of roundabout = 2.7 m/s

r = Radius of roundabout = 1 m = R

I = Moment of inertia

Her angular momentum

$L_i=mvr\\\Rightarrow L_i=43\times 2.7\times 1\\\Rightarrow L_i=116.1\ kgm^2/s$

Magnitude of angular momentum is 116.1 kgm²/s

Here the angular momentum is conserved

$L_f=L_i\\\Rightarrow I\omega=L_i\\\Rightarrow (\frac{1}{2}MR^2+mr^2)\omega=116.1\\\Rightarrow \omega=\frac{116.1}{\frac{1}{2}\times 120\times 1^2+43\times 1^2}\\\Rightarrow \omega=1.12718\ rad/s$

Angular speed of the roundabout is 1.12718 rad/s

Initial kinetic energy

$K_i=\frac{1}{2}mv^2\\\Rightarrow K_i=\frac{1}{2}43\times 2.7^2\\\Rightarrow K_i=156.735\ J$

Final kinetic energy

$K_f=\frac{1}{2}I\omega^2\\\Rightarrow K_f=\frac{1}{2}\times (\frac{1}{2}\times 120\times 1^2+43\times 1^2)\times 1.12718^2\\\Rightarrow K_f=65.43253\ J$

The overall kinetic energy decreases as can be seen. This loss is converted to heat.

5 0

3 years ago

I will give you branilest

morpeh [17]

Answer:

Explanation:

if you bounce a tennis ball, it will come back up as an equal reaction to your action (dropping it). there is an equal but opposite reaction in this scenario, demonstrating newton's third law.

6 0

4 years ago

Read 2 more answers

A 0.10 newton spring toy with a spring constant of 160 newtons per meter is compressed 0.05 meter before it is launched. When re

forsale [732]

Answer:

(1) V = 0.2 J (2) 0.05J

Explanation:

Solution

Given that:

K = 160 N/m

x = 0.05 m

Now,

(1) we solve for the initial potential energy stored

Thus,

V = 1/2 kx² = 0.5 * 160 * (0.05)²

Therefore V = 0.2 J

(2)Now, we solve for how much of the internal energy is produced as the toy springs up to its maximum height.

By using the energy conversion, we have the following

ΔV = mgh

=(0.1/9.8) * 9.8 * 1.5 = 0.15J

The internal energy = 0.2 -0.15

=0.05J

8 0

3 years ago

On an aircraft carrier, a jet can be catapulted from 0 to 240 km/h in 2.10 s. If the average force exerted by the catapult is 9.

Leya [2.2K]

<h2>Answer</h2>

The answer is 29495.3 kg

<h2>Explanation</h2>

As we know, the Newton's Second Law of Motion

$Force = Mass * Acceleration$

$F = ma$

The F exerted by catapult = 9.35 * $10^5$

The Time is = 2.10 s

Velocity of the catapult = 240 km/h = 66.6 m/s (240*1000 m /3600 s)

The mass of jet = ?

First detrmine the acceleration as

{/tex}Acceleration = Velocity/Time {/tex}

$Acceleration = 66.6 ms^{-1}/2.1 s$

$Acceleration (a) = 31.7 ms^{-2}$

Rearrange the formaula as

$m= F/a$

$m= 9.35 * 10^5 N /31.7 ms^{-2}$

$m = 29495.3 kg$

The mass will be 29495.3 kg

4 0

4 years ago