1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Klio2033 [76]
3 years ago
13

A 1.5kg mass attached to an ideal spring oscillates horizontally with an amplitude of 0.50m. The spring constant is 85 n/m. what

is the frequency of the mass's motion?
Physics
1 answer:
Stolb23 [73]3 years ago
5 0

Answer:

frequency of the mass motion f ≅ 1.2 Hz

Explanation:

Given that:

Mass m = 1.5 kg

Amplitude A = 0.50 m

Spring constant k = 85 n/m

The frequency can be calculated by using the formula:

f = \frac{1}{2 \pi} \sqrt{\frac{k}{m} }

f = \frac{1}{2 \pi} \sqrt{\frac{85}{1.5} }

f = 1.198 Hz

frequency of the mass motion f ≅ 1.2 Hz

You might be interested in
Convert 68852 millijoules into Calories. (Write your answer in the decimal form. Do not include units in your answer).
alex41 [277]

Answer: 68852 millijoules = 16.46 calories

Explanation:

Given;

Convert 68852 millijoules to calories.

1 calorie = 4.184J = 4184millijoules

Therefore,

1 millijoule = 1/4184 calories

68852 millijoule = 68852 × 1/4184 calories

= 16.46 calories

6 0
3 years ago
What environments does tornado not occur in?
Nadusha1986 [10]
The winter I think would be the answer
5 0
2 years ago
Read 2 more answers
I’m not sure how to solve this
spayn [35]

Answer:

Option 10. 169.118 J/KgºC

Explanation:

From the question given above, the following data were obtained:

Change in temperature (ΔT) = 20 °C

Heat (Q) absorbed = 1.61 KJ

Mass of metal bar = 476 g

Specific heat capacity (C) of metal bar =?

Next, we shall convert 1.61 KJ to joule (J). This can be obtained as follow:

1 kJ = 1000 J

Therefore,

1.61 KJ = 1.61 KJ × 1000 J / 1 kJ

1.61 KJ = 1610 J

Next, we shall convert 476 g to Kg. This can be obtained as follow:

1000 g = 1 Kg

Therefore,

476 g = 476 g × 1 Kg / 1000 g

476 g = 0.476 Kg

Finally, we shall determine the specific heat capacity of the metal bar. This can be obtained as follow:

Change in temperature (ΔT) = 20 °C

Heat (Q) absorbed = 1610 J

Mass of metal bar = 0.476 Kg

Specific heat capacity (C) of metal bar =?

Q = MCΔT

1610 = 0.476 × C × 20

1610 = 9.52 × C

Divide both side by 9.52

C = 1610 / 9.52

C = 169.118 J/KgºC

Thus, the specific heat capacity of the metal bar is 169.118 J/KgºC

6 0
2 years ago
Which three statements about electromagnetic radiation are true?
grandymaker [24]
I think that numbers one, three, and four are true
3 0
3 years ago
Read 2 more answers
Tectonic plate movement is the reason why northern California has a very different landscape than southern California. Two diffe
Studentka2010 [4]

Answer:

I don't know the answer I need points before I fail my math test

3 0
2 years ago
Other questions:
  • If a typical smelt weighs 225 g, what is the total mass of pcbs in a smelt in the great lakes? If a typical smelt weighs 225 g,
    9·1 answer
  • A 24-cm-diameter vertical cylinder is sealed at the top by a frictionless 15 kg piston. The piston is 90 cm above the bottom whe
    5·1 answer
  • A roller coaster slows as it travels up a hill<br> a) speed <br> b) velocity <br> c) acceleration
    8·1 answer
  • How can a driver steer a car traveling at constant speed so that the magnitude of the acceleration remains constant. (Assume tha
    13·1 answer
  • A flea jumps by exerting a force of 1.09 ✕ 10−5 N straight down on the ground. A breeze blowing on the flea parallel to the grou
    7·1 answer
  • What is the vertical displacement below any line?
    13·1 answer
  • Ruby is out with her friends. Misfortune occurs and
    6·1 answer
  • !!!!!PLEASE ANSWER CORRECTLY!! I DESPERATLY NEED HELP!!!!!
    6·1 answer
  • Which is a property of bases?
    8·2 answers
  • Calculate the resistance in a circuit with a 16 volt battery and 4 amps of current.
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!