Answer:
a)
Explanation:
- A block sliding down an inclined plane, is subject to two external forces along the slide.
- One is the component of gravity (the weight) parallel to the incline.
- If the inclined plane makes an angle θ with the horizontal, this component (projection of the downward gravity along the incline, can be written as follows:
(taking as positive the direction of the movement of the block)
- The other force, is the friction force, that adopts any value needed to meet the Newton's 2nd Law.
- When θ is so large, than the block moves downward along the incline, the friction force can be expressed as follows:
- The normal force, adopts the value needed to prevent any vertical movement through the surface of the incline:
- In equilibrium, both forces, as defined in (1), (2) and (3) must be equal in magnitude, as follows:
- As the block is moving, if the net force is 0, according to Newton's 2nd Law, the block must be moving at constant speed.
- In this condition, the friction coefficient is the kinetic one (μk), which can be calculated as follows:
Answer:
Explanation:
Given that:
distance (z) = 7.86 m
mass of the person = 81.7 kg
Acceleration (a) = 0.729 m/s²
By using Newton's second law along the vertical axis:
T = 81.7 (0.729 +9.8)
T = 860.22 N
The work done now is:
Answer:
0.733J/g°C
Explanation:
Using the formula
Q=mcΔθ
Q=38.5J, c=? , m=17.5g , Δθ=3°C
c= Q/(mΔθ)
c=0.733J/g°C
What are the given choices?
The answer is d) The 1.5 kg ball because it has more momentum.
Momentum = Impulse = Mass + Velocity
= 2 * 10 = 20 kg*m/s
= 1.5 * 20 = 30 kg*m/s
hence the 1.5 kg ball has greater momentum and impulse.
Source: http://forumvu.com/Thread-GSC101-Assignment-1-Solution-Fall-2017