Acceleration x time = velocity
Since you're given acceleration and time, just plug the values into the equation.
3

x 1.1 s = ?
Solve that equation, and remember your velocity should be in m/s.
Answer:
v1 = 15.90 m/s
v2 = 8.46 m/s
mechanical energy before collision = 32.4 J
mechanical energy after collision = 32.433 J
Explanation:
given data
mass m = 0.2 kg
speed = 18 m/s
angle = 28°
to find out
final velocity and mechanical energy both before and after the collision
solution
we know that conservation of momentum remain same so in x direction
mv = mv1 cosθ + mv2cosθ
put here value
0.2(18) = 0.2 v1 cos(28) + 0.2 v2 cos(90-28)
3.6 = 0.1765 V1 + 0.09389 v2 ................1
and
in y axis
mv = mv1 sinθ - mv2sinθ
0 = 0.2 v1 sin28 - 0.2 v2 sin(90-28)
0 = 0.09389 v1 - 0.1768 v2 .......................2
from equation 1 and 2
v1 = 15.90 m/s
v2 = 8.46 m/s
so
mechanical energy before collision = 1/2 mv1² + 1/2 mv2²
mechanical energy before collision = 1/2 (0.2)(18)² + 0
mechanical energy before collision = 32.4 J
and
mechanical energy after collision = 1/2 (0.2)(15.90)² + 1/2 (0.2)(8.46)²
mechanical energy after collision = 32.433 J
Answer:
x component is 60.60 N and y component is 35 N ⇒ answer A
Explanation:
A boy is pulling a wagon with a force of 70.0 N directed at an angle
of 30 degrees above the horizontal then,
is the horizontal component of the force in the direction
of positive part of x-axis
is the vertical component of the force force in the direction
of positive part of y-axis
The x component of the force
is the force multiplied by
cos(30)°
The y component of the force
is the force multiplied by
sin(30)°
→ The x component
= F cos(30)
→ The x component
= 70 cos(30) = 60.60 N
→ The y component
= F sin(30)
→ The y component
= 70 sin(3) = 35 N
<em>x component is 60.60 N and y component is 35 N</em>
Answer:
Option (C) is the answer
Explanation:
may be it is possible if that we stand so far