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dem82 [27]
3 years ago
11

What is a vector, i couldn’t really find an answer online

Physics
2 answers:
Julli [10]3 years ago
8 0

It's a measurement that's made up of two separate quantities ... its size AND its direction.

Some examples of vectors: force, displacement, velocity, acceleration. These things all have directions.

If one car is driving North at 30 mph and another car is driving West at 30 mph, then both cars have the same speed, but they have different velocities.

Setler79 [48]3 years ago
5 0
Many measurements can be described by using just one number. These are called SCALAR quantities. Examples are temperature, the wavelength of light in a laser beam, and one's weight or height. There are also other things that need both a direction described as well as the number that tells you how much of whatever you have. A simple example would be the movement of an airplane in flight. Not only do you need to know its speed (the scalar), but you also need to know its direction of flight (up, down, east, west, and so on). These are called VECTOR quantities. (For the airplane example, the vector that describes the direction and speed is called the VELOCITY vector.)

When you see vectors used in math or science books, they usually stick to 2 dimensional problems (i.e., the surface of the book page) for simplicity. Vectors are shown as a line segment with an arrow head at one end. In this way, the direction of the vector is obvious. The length of the line represents the amount of whatever (say, the speed of the airplane).

The neat thing about vectors is that one can also add them (as long as they represent the same thing) geometrically to find a new vector. For example, imagine a plane flying horizontally in a northerly direction at 500 miles per hour. However, there is also a wind blowing in a westerly direction at 100 miles per hour. By adding the velocity vectors for the plane and the wind, one can find the vector that properly describes the airplane's flight path (and speed)
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A dancer starts 3 meters from the curtain then moves 8 meters from the curtain in 15 seconds. What was his velocity?
myrzilka [38]
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3 years ago
You're driving in a car at 50 km/h and bump into a car ahead traveling at 48 km/h in the same direction. the speed of impact is
salantis [7]

To solve this problem, we must remember about the law of conservation of momentum. The initial momentum mist be equal to the final momentum, that is:

m1 v1 + m2 v2 = (m1 + m2) v’

where v’ is the speed of impact

Since we are not given the masses of each car m1 and m2, so let us assume that they are equal, such that:

m1 = m2 = m

Which makes the equation:

m v1 + m v2 = (2 m) v’

Cancelling m and substituting the v values:

50 + 48 = 2 v’

2 v’ = 98

v ‘ = 49 km/h

 

<span>The speed of impact is 49 km/h.</span>

6 0
3 years ago
Why would you expect sodium (Na) to react strongly with chlorine (Cl)?
Snowcat [4.5K]
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5 0
3 years ago
Read 2 more answers
This equation is used to calculate the properties of a gas under nonideal conditions.
goblinko [34]

Answer:

Van der Waal's equation

Explanation:

The Van der Waal's equation is use to calculate the properties of a gas under nonideal or real gases conditions.

(P + \frac{an^2}{V^2})(V-nb) = nRT .

Here P, V ,T ,n and R have usual meaning as in the ideal gas equation

that is PV=nRT

with the difference of constant a and b.  a and b are constants representing magnitude of intermolecular attraction  and excluded volume respectively respectively.

5 0
4 years ago
Imagine that asteroid A that has an escape velocity of 50 m/s. If asteroid B has twice the mass and twice the radius, it would h
padilas [110]

Answer:

The same as the escape velocity of asteorid A (50m/s)

Explanation:

The escape velocity is described as follows:

v=\sqrt{\frac{2GM}{R}}

where G is the universal gravitational constant, M is the mass of the asteroid and R is the radius

and since the scape velocity is 50m/s:

50m/s=\sqrt{\frac{2GM}{R}}

Now, if the astroid B has twice mass and twice the radius, we have that tha mass is: 2M

and the radius is: 2R

inserting these values into the formula for escape velocity:

v=\sqrt{\frac{2G(2M)}{2R} } =\sqrt{\frac{4GM}{2R} } =\sqrt{\frac{2GM}{R} }

and we have found that 50m/s=\sqrt{\frac{2GM}{R}}, so the two asteroids have the same escape velocity.

We found that the expression for escape velocity remains the same as for asteroid A, this because both quantities (radius and mass) doubled, so it does not affect the equation.

The answer is

Asteroid B would have an escape velocity the same as the escape velocity of asteroid A

7 0
3 years ago
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