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3 years ago

Find the area of this figure.

Mathematics

1 answer:

ryzh [129]3 years ago

7 0

Answer:

1824 square inches

Step-by-step explanation:

First, separate the figure into two sections. The triangle on top, and the rectangle on the bottom.

to get the area of the triangle, simply multiply height times width and divide by two.

48 x 12 = 576

576/2 = 288

the area of the triangle is 288 sq in

next, multiply the height and width of the rectangle to get its area.

32 x 48 = 1536

add 1536 to 288 to get the area of the complete figure

1536 + 288 = 1824

the answer is 1824 square inches

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How can you get equation b from equation A. 3(x+2)=18 B. X+2=18

Rzqust [24]

Answer:

We start with the equation:

A: 3*(x + 2) = 18

And we want to construct equation B:

B: X + 2 = 18

where I suppose that X is different than x.

Because in both equations the right side is the same thing, then the left side also should be the same thing, this means that:

3*(x + 2) = X + 2

Now we can isolate the variable x.

(x + 2) = (X + 2)/3

x = (X + 2)/3 - 2

Then we need to replace x by (X + 2)/3 - 2 in equation A, and we will get equation B.

Let's do it:

A: 3*(x + 2) = 18

Now we can replace x by = (X + 2)/3 - 2

3*( (X + 2)/3 - 2 + 2) = 18

3*( (X + 2)/3 ) = 18

3*(X + 2)/3 = 18

(X + 2) = 18

Which is equation B.

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2 years ago

Use a transformation to solve the equation. w/4 = 8 can you also leave a detailed explanation on how this equation = 32

OverLord2011 [107]

Answer:

w=32

Step-by-step explanation:

w/4 = 8

4/1 * w/4 = 8*4

w=32

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3 years ago

Variation table of this <br> g(x)=2x^3 -x^2 -4x +6

Mrac [35]

Answer:

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3 years ago

Make d the subject of the formula h=d/3+2

Pani-rosa [81]

Answer: D=3(h-2)

Explanation —>

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2 years ago

If you run for 0.4 hours at 7 mph, how fast should you walk during the next 0.8 hours to have the average speed of 5 mph?

Fantom [35]

Answer:

4 mph

Step-by-step explanation:

The average speed of an object is given by the total distance covered by the time taken:

$v=\frac{d}{t}$

where

d is the total distance covered

t is the time taken

in the first part, the person runs for 0.4 hours at a speed of 7 mph, so the distance covered in the 1st part is

$d_1 = v_1 t_1 = (7)(0.4)=2.8 mi$

Then the distance covered in the second part is $d_2$ , so the total distance is

$d=2.8+d_2$ (1)

The total time elapsed is 0.4 hours (first part) + 0.8 hours (second part), so

$t=0.4+0.8=1.2 h$

So we can write the average speed as

$v=\frac{2.8+d_2}{1.2}$ (1)

We want the average speed to be 5 mph,

v = 5 mph

Therefore we can rearrange eq.(1) to find d2:

$d_2 = 1.2v-2.8 = (1.2)(5)-2.8=3.2 mi$

And therefore, the speed in the second part must be

$v_2=\frac{d_2}{t_2}=\frac{3.2}{0.8}=4 mph$

4 0

3 years ago