Answer:
The probability of selecting randomly 6 packets such that the first 4 contain cocaine and 2 not is 0.3522.
Step-by-step explanation:
Probabilities of selecting 4 packets with the ilegal substance:
= 
Combinassions possible= 1365
Probabilities of selecting 2 packets with white powder:
= 
Combinations possible= 10
Probabilities of selecting 6 packets from the totality of them:
= 
Combinations possible= 38760
The probability of picking 4 with the substance and 2 with only white powder is:
= 0.3522
I hope this answer helps you.
Answer:
x = 3
Step-by-step explanation:
Set up as proportion and cross multiply to solve:
3/4 = 2.25/x
x = 3
Its a rational number because whole numbers dont consist of decimals nor fractions
Answer:
B
Step-by-step explanation:
We have to look at the full dot