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vagabundo [1.1K]
3 years ago
7

Ms. Neeson wants to share $1 equally among 7 students. What fraction of a dollar will each student get?

Mathematics
2 answers:
Ainat [17]3 years ago
8 0

each student will get 1/7 of a dollar

dimulka [17.4K]3 years ago
4 0

Answer:

1/7

Step-by-step explanation:

$1, 7 students

simply put 1 over 7 and you've got your fraction.

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First you multiply 4 by 5 and wind up with 20
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You take out all the nines you can from 28, three in this case.
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Your total thing is 20+27÷9+1÷9
That equals 20+3+1÷9
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The entire length of the Appalachian Trail is 2,160 miles. How long would it take you to hike the full length of the trail?
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3 years ago
This is a number system which uses a base of 10. The valid digits are 0 to 9.
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7 0
3 years ago
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A sample of 5 strings of thread is randomly selected and the following thicknesses are measured in millimeters. Give a point est
xxTIMURxx [149]

Answer:

Point estimate for the population variance = 3.92 * 10^{-3} .

Step-by-step explanation:

We are given that a sample of 5 strings of thread is randomly selected and the following thicknesses are measured in millimeters ;

       X                       X - Xbar                                         (X-Xbar)^{2}

      1.13            1.13 - 1.188 = -0.058                                 3.364 * 10^{-3}

      1.15            1.15 - 1.188 = -0.038                                 1.444 * 10^{-3}    

      1.15            1.15 - 1.188 = -0.038                                 1.444 * 10^{-3}

      1.24           1.24 - 1.188 = 0.052                                 2.704 * 10^{-3}

      1.27           1.27 - 1.188 = 0.082                               <u>  6.724 * </u>10^{-3}<u>    </u>

                                                                    \sum (X-Xbar)^{2} <u>= 0.01568   </u>

Firstly, Mean of above data, Xbar = \frac{\sum X}{n} = \frac{1.15+1.24+1.15+1.27+1.13}{5} = 1.188

Point estimate of Population Variance = Sample variance

                                                               = \frac{\sum (X-Xbar)^{2}}{n-1} = \frac{0.01568}{4} = 3.92 * 10^{-3} .

Therefore, point estimate for the population variance = 3.92 * 10^{-3} .

       

5 0
3 years ago
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