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3 years ago

What is the sum of the arithmetic sequence 8, 14, 20 ..., if there are 22 terms?

Mathematics

2 answers:

timama [110]3 years ago

5 0

Answer: I'm pretty sure its 1562

prohojiy [21]3 years ago

3 0

Answer:

The sum of 22 terms of given AP = 1562

Step-by-step explanation:

Formula:-

Sum of n terms of AP,

Sₙ= (n/2)[2a + (n - 1)d]

<u>To find the sum of 22 terms</u>

Here. a = 8, d = 6 and n = 22

Sₙ= (n/2)[2a + (n - 1)d]

S₂₂ = (22/2)[2*8 + (22 - 1)*6]

= 11[16 + 126] = 11 * 142 = 1562

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In a competition between players X and Y, the first player to win three games in a row or a total of four games wins. How many w

OLEGan [10]

Answer:

The competition can be played in 7 different ways

Step-by-step explanation:

First game : X

Second game : Y

Third game : Y

After that either X or Y can win

<h3>¹Case - 1: Y wins the fourth game:</h3>

The competition ends with Y winning as he/she won 3 games in a row

<h3>Case - 2: X wins the fourth game:</h3>

more games are required to decide the winner

<h3>Sub-case - a: X wins the fifth game:</h3>

more games are required to decide the winner

<h3>²Sub-sub-case - i: X wins the sixth game:</h3>

The competition ends with X winning as he/she won 3 games in a row

<h3>³⁻⁴Sub-sub-case - ii: Y wins the sixth game:</h3>

The competition ends after the seventh game. Whoever wins seventh game wins the competition as he/she would've won 4 games in total by then.

<h3>Sub-case - b: Y wins the fifth game:</h3>

more games are required to decide the winner

<h3>⁵Sub-sub-case - i: Y wins the sixth game:</h3>

The competition ends with Y winning as he/she won 4 games in total

<h3>⁶⁻⁷Sub-sub-case - ii: X wins the sixth game:</h3>

The competition ends after the seventh game. Whoever wins seventh game wins the competition as he/she would've won 4 games in total by then.

∴<u>The competition can be played in 7 different ways</u>

7 0

3 years ago

PLS HELP!

wolverine [178]

Given:

Alexis has a rectangular backyard that is 50 yards by 55 yards.

She wants to build a fence that stretches diagonally from one corner to the opposite corner.

To find:

The length of the fencing she needs.

Solution:

We have,

Length = 50 yards

Width = 55 yards

We know that, the diagonal of a rectangle is

$Diagonal=\sqrt{length^2+width^2}$

$Diagonal=\sqrt{(50)^2+(55)^2}$

$Diagonal=\sqrt{2500+3025}$

$Diagonal=\sqrt{5525
}$

On further simplification, we get

$Diagonal=74.3303437$

$Diagonal\approx 74.3$

Therefore, the length of the required fencing is 74.3 yards.

8 0

3 years ago

Could someone please help me with this problem and possibly explain if you can? (Will give up brainiest answer if correct, if po

Andrej [43]

To find the answer you need to find the square root of e^2 to get e so what you do to one side of the equation you do to the other side of the equation so find the square root of 0.36.
e=positive or negative 0.6

3 0

3 years ago

Four times what gets you fourtheight

lakkis [162]

I think you mean 48. 4 * x = 48. x = 48/4 = 12

5 0

3 years ago

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lesya692 [45]

$3(14 - 5x) = 16 - 12x$

Distribute 3 throught the parentheses

$42 - 15x = 16-12x$

Move the variable to the left-hand side and change its sign

$42 - 15x + 12x = 16$

Move the constant to the right-hand side and change its sign

$- 15x+12x=16 - 42$

Collect like terms

$- 3x = - 26$

Divide both sides of the equation by -3

$\boxed{x = \frac{26}{3} }$

6 0

2 years ago

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