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seraphim [82]
3 years ago
14

What is the sum of the arithmetic sequence 8, 14, 20 ..., if there are 22 terms?

Mathematics
2 answers:
timama [110]3 years ago
5 0

Answer: I'm pretty sure its 1562

prohojiy [21]3 years ago
3 0

Answer:

The sum of 22 terms of given AP = 1562

Step-by-step explanation:

Formula:-

Sum of n terms of AP,

Sₙ= (n/2)[2a + (n - 1)d]

<u>To find the sum of 22 terms</u>

Here. a = 8, d = 6 and n = 22

Sₙ= (n/2)[2a + (n - 1)d]

S₂₂ = (22/2)[2*8 + (22 - 1)*6]

  = 11[16 + 126] = 11 * 142 = 1562

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Endpoint: (9,-10), midpoint: (4,8)
Alika [10]

Answer:

( -1 , 26)

Step-by-step explanation:

So since you need to find the other endpoint, you would follow these steps:

1.) 4 = \frac{9 + x}{2\\}

2.) 8 = 9 + x  ( you just multiplied the 2 to the 4 to get 8)

3.) -1 = x  (just solve it like a regular equation, so just subtract 9 on both sides                  to get rid of it and that leaves you with -1 = x)

You took the x values of both points and put them in the equation.

And its the same for y

1.) 8 = \frac{-10 + y}{2}

2.) 16 = -10 + y

3.) 26 = y   (you added the 10 on both sides because the 10 was negative and that took the 10 out and so it left you with 26 = y)

5 0
3 years ago
A group of students are meeting in the cafeteria. 70 students have already arrived. This is 35% of the group. How many are in th
sesenic [268]
There are 200 students in the group.

To find this, you divide 70 by 0.35 (35%). This will give you 200. To check this, multiply 200 by 0.35 and you will get 70. Thus making 200 the answer.

I hope this helps!
4 0
3 years ago
Read 2 more answers
"Find the sum of the first 50 term in this sequence 4, 7, 10, 13, ...". How do i do this without writing them all out, and how d
melisa1 [442]
First term ,a=4 , common difference =4-7=-3, n =50
sum of first 50terms= (50/2)[2×4+(50-1)(-3)]
=25×[8+49]×-3
=25×57×-3
=25× -171
= -42925
derivation of the formula for the sum of n terms
Progression, S
S=a1+a2+a3+a4+...+an

S=a1+(a1+d)+(a1+2d)+(a1+3d)+...+[a1+(n−1)d]   →   Equation (1)

S=an+an−1+an−2+an−3+...+a1

S=an+(an−d)+(an−2d)+(an−3d)+...+[an−(n−1)d]   →   Equation (2)

Add Equations (1) and (2)
2S=(a1+an)+(a1+an)+(a1+an)+(a1+an)+...+(a1+an)

2S=n(a1+an)
S=n/2(a1+an)

Substitute an = a1 + (n - 1)d to the above equation, we have
S=n/2{a1+[a1+(n−1)d]}
S=n/2[2a1+(n−1)d]
5 0
3 years ago
The measure of the supplement angle is fourteen times greater than its supplement
disa [49]
Let's assume you have supplement angle
x
Now when you talk about multiplication you can simply say...
14x = y
And that will give you the answer.
6 0
3 years ago
a countrys population in 1995 was 175 million . in 2000 it was 181 million estimate the population in 2020 using the exponential
galben [10]
In 5 years it grew 6 mill (181-175=6). Formula: 6(20/5)+181=X. multiply 6 by 4 (the number of five years in twenty years): 24. 24+181=205 million :)
7 0
3 years ago
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