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seraphim [82]
4 years ago
14

What is the sum of the arithmetic sequence 8, 14, 20 ..., if there are 22 terms?

Mathematics
2 answers:
timama [110]4 years ago
5 0

Answer: I'm pretty sure its 1562

prohojiy [21]4 years ago
3 0

Answer:

The sum of 22 terms of given AP = 1562

Step-by-step explanation:

Formula:-

Sum of n terms of AP,

Sₙ= (n/2)[2a + (n - 1)d]

<u>To find the sum of 22 terms</u>

Here. a = 8, d = 6 and n = 22

Sₙ= (n/2)[2a + (n - 1)d]

S₂₂ = (22/2)[2*8 + (22 - 1)*6]

  = 11[16 + 126] = 11 * 142 = 1562

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72.2 m

Step-by-step explanation:

65 km/1 h = (65000 m / 3600s) = 18.05 m/s

Distance = speed * time = 18.05 m/s*4 s = 72.2 m

8 0
3 years ago
Use the five number summary calculated in part C to create a box plot representing the data. Draw a box plot representing the fo
Alex777 [14]

Answer: Minimum: 20

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3 years ago
The graph below shows graph of f (x), its derivative f '(x), and its second derivative f "(x). Which of the following is the cor
Jet001 [13]

Answer:

A is f ", B is f, C is f '.

Step-by-step explanation:

Your answer is correct.  B is the original function f.  It has a local maximum at x=0, and local minimums at approximately x=-3/2 and x=3/2.

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8 0
3 years ago
Need help!!!!!!!!!!!!!!
lisov135 [29]
It is the last answer that is the correct one 

6 0
3 years ago
You back packed for a distance of 15.75 miles today. You back packed at an average speed of 1.26 miles per hour, how long did yo
Anna [14]

Let us first concentrate and write down all the information's given in the question. Based on these information's the answer to the question can be easily deduced.
Distance for which back packing was done = 15.75 miles
Average speed of back packing = 1.26 miles/hour
Since
Speed = Distance/Time
Time = Distance/speed
Time spend for back packing = 15.75/1.26 hour
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So the total time taken for back packing is 12.5 hours. I hope this is the answer you were looking for and the procedure is clear to you.
7 0
3 years ago
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