<span>A = P (1 + r/n)<span> (nt)
</span></span>A<span> = the future value of the investment</span>
P<span> = (the initial deposit or loan amount)</span>
r<span> = the annual interest rate (decimal)</span>
n<span> = the number of times that interest is compounded per year</span>
t<span> = the number of years the money is invested
</span>
Answer: x = -5, 3/2 y = 10, 7/2
Explanation:
y = 2x^2 + 6x - 10 (1)
y = - x + 5 (2)
=> 2x^2 + 6x - 10 = - x + 5
2x^2 - 7x - 15 = 0
(2x - 3)(x + 5) = 0
=> 2x - 3 = 0
2x = 3
x = 3/2
=> x + 5 = 0
x = -5
According to (2):
y = -x + 5
y = -(-5) + 5
y = 5 + 5 = 10
y = -x + 5
y = -(3/2) + 5
y = -(3/2) + 10/2
y = 7/2
Pretend * is counter
* * *
* * *
the word problem could be in a box of chocolates there is 3 rows and 2 chocolates in each row how many chocolates are there total.
Given:
The given quadratic polynomial is :

To find:
The quadratic polynomial whose zeroes are negatives of the zeroes of the given polynomial.
Solution:
We have,

Equate the polynomial with 0 to find the zeroes.

Splitting the middle term, we get




The zeroes of the given polynomial are -3 and 4.
The zeroes of a quadratic polynomial are negatives of the zeroes of the given polynomial. So, the zeroes of the required polynomial are 3 and -4.
A quadratic polynomial is defined as:




Therefore, the required polynomial is
.