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Sedbober [7]
3 years ago
6

An egg carton holds 12 eggs. A breakfast buffet uses 96 eggs by 8am. When the buffet ends at 10:30, a total of 156 eggs were use

d. How many cartons of eggs were used after 8 am?
Mathematics
1 answer:
Kaylis [27]3 years ago
4 0

Answer:

5 cartons of eggs were used.

Step-by-step explanation:

Since there are a total of 156 eggs used, and 96 were already used, you subtract 156 - 96 = 60. Since there 12 eggs in each carton, you divide 60 by 12 to get 5.

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Amelia, Luis, Shauna, and Clarence used different approaches to solve the inequality 7.2b + 6.5 > 4.8b – 8.1. Which student's
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Answer: Luis’s, because he flipped the inequality sign when he subtracted

Step-by-step explanation:

Here is the complete question:

Amelia, Luis, Shauna, and Clarence used different approaches to solve the inequality

7.2b + 6.5 > 4.8b – 8.1.

Amelia started by subtracting 7.2b from both sides to get 6.5 > –2.4b – 8.1.

Luis started by subtracting 4.8b from both sides to get 2.4b + 6.5 < – 8.1.

Shauna started by subtracting 6.5 from both sides to get 7.2b > 4.8b – 14.6.

Clarence started by adding 8.1 to both sides to get 7.2b + 14.6 > 4.8b.

Which student’s first step was incorrect, and why?

a. Amelia’s, because the variable term must be isolated on the left side

b. Luis’s, because he flipped the inequality sign when he subtracted

c. Shauna’s, because she did not apply the subtraction property of equality properly.

d. Clarence’s, because the terms he added together were not like terms.

The inequality given is:

7.2b + 6.5 > 4.8b – 8.1.

We are informed that Luis started by subtracting 4.8b from both sides to get 2.4b + 6.5 < – 8.1.

If Luis started by subtracting 4.8b from both sides, he should get:

7.2b + 6.5 > 4.8b – 8.1.

7.2b + 6.5 - 4.8b > 4.8b – 8.1 - 4.8b

2.4b + 6.5 > - 8.1

But looking critically, we would realise that what Luis got us different as the inequality sign has been changed from greater than to less than and this is incorrect.

The inequality sign can only be flipped in case whereby there's a division or multiplication of a negative number from both sides.

Therefore, Luis’s first step was incorrect because he flipped the inequality sign when he subtracted.

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A random sample of 49 measurements from one population had a sample mean of 15, with sample standard deviation 5. An independent
kotykmax [81]

Answer:

Comparing the p value with the significance level \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and the difference between the two groups is significantly different.  

Step-by-step explanation:

\bar X_{1}=15 represent the mean for sample 1

\bar X_{2}=18 represent the mean for sample 2

s_{1}=5 represent the sample standard deviation for 1  

s_{f}=6 represent the sample standard deviation for 2  

n_{1}=49 sample size for the group 2  

n_{2}=64 sample size for the group 2  

\alpha=0.01 Significance level provided

t would represent the statistic (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the difference in the population means, the system of hypothesis would be:  

Null hypothesis:\mu_{1}-\mu_{2}=0  

Alternative hypothesis:\mu_{1} - \mu_{2}\neq 0  

We don't have the population standard deviation's, so for this case is better apply a t test to compare means, and the statistic is given by:  

t=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}} (1)

And the degrees of freedom are given by df=n_1 +n_2 -2=49+64-2=111  

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

With the info given we can replace in formula (1) like this:  

t=\frac{(15-18)-0}{\sqrt{\frac{5^2}{49}+\frac{6^2}{64}}}}=-2.897

P value

Since is a bilateral test the p value would be:  

p_v =2*P(t_{111}  

Comparing the p value with the significance level \alpha=0.01 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and the difference between the two groups is significantly different.  

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