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Sedbober [7]
3 years ago
6

An egg carton holds 12 eggs. A breakfast buffet uses 96 eggs by 8am. When the buffet ends at 10:30, a total of 156 eggs were use

d. How many cartons of eggs were used after 8 am?
Mathematics
1 answer:
Kaylis [27]3 years ago
4 0

Answer:

5 cartons of eggs were used.

Step-by-step explanation:

Since there are a total of 156 eggs used, and 96 were already used, you subtract 156 - 96 = 60. Since there 12 eggs in each carton, you divide 60 by 12 to get 5.

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Alex invests $12,500 in a savings account that pays 5% interest compounded quarterly. Approximately how much money will he have
Gala2k [10]
<span>A = P (1 + r/n)<span> (nt)
</span></span>A<span> = the future value of the investment</span>
P<span> = (the initial deposit or loan amount)</span>
r<span> = the annual interest rate (decimal)</span>
n<span> = the number of times that interest is compounded per year</span>
t<span> = the number of years the money is invested 
</span>
8 0
3 years ago
The sum of two numbers is 63. The larger number is 23 more than the smaller number. What are the numbers?
Sunny_sXe [5.5K]

x+y=63

x=y+23

y+23+y =63

2y +23 = 63

2y =40

y=40/2 =20

y = 20

x = 20+23=43

the numbers are 20 & 43

5 0
2 years ago
Read 2 more answers
What are the solutions to the system of equations? {y=2x2+6x−10 y=−x+5
inessss [21]
Answer: x = -5, 3/2 y = 10, 7/2

Explanation:

y = 2x^2 + 6x - 10 (1)
y = - x + 5 (2)

=> 2x^2 + 6x - 10 = - x + 5
2x^2 - 7x - 15 = 0
(2x - 3)(x + 5) = 0
=> 2x - 3 = 0
2x = 3
x = 3/2
=> x + 5 = 0
x = -5

According to (2):

y = -x + 5
y = -(-5) + 5
y = 5 + 5 = 10

y = -x + 5
y = -(3/2) + 5
y = -(3/2) + 10/2
y = 7/2

3 0
3 years ago
Read 2 more answers
draw3 rows with 2 counters in each row write a word problem that can be acted out using these counters
Gnoma [55]
Pretend * is counter

*   *   *
*   *   *

the word problem could be in a box of chocolates there is 3 rows and 2 chocolates in each row how many chocolates are there total.
6 0
3 years ago
Read 2 more answers
Construct a quadratic polynomial whose zeroes are negatives of the zeroes of the
sp2606 [1]

Given:

The given quadratic polynomial is :

x^2-x-12

To find:

The quadratic polynomial whose zeroes are negatives of the zeroes of the given polynomial.

Solution:

We have,

x^2-x-12

Equate the polynomial with 0 to find the zeroes.

x^2-x-12=0

Splitting the middle term, we get

x^2-4x+3x-12=0

x(x-4)+3(x-4)=0

(x+3)(x-4)=0

x=-3,4

The zeroes of the given polynomial are -3 and 4.

The zeroes of a quadratic polynomial are negatives of the zeroes of the given polynomial. So, the zeroes of the required polynomial are 3 and -4.

A quadratic polynomial is defined as:

x^2-(\text{Sum of zeroes})x+\text{Product of zeroes}

x^2-(3+(-4))x+(3)(-4)

x^2-(-1)x+(-12)

x^2+x-12

Therefore, the required polynomial is x^2+x-12.

4 0
3 years ago
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