1) f(x)=2x+6
f(2)=2(2)+6
=4+6
=10
2)f(x)=3x
f(a+1)=3(a+1)
=3a+3
3)f(x)=3x-1 and g(x)=5x+3
f(2)=3(2)-1
f(2)=6-1
=5
g(3)=5x+3
=5(3)+32
=15+3
=18
f(2)+f(3)=5+18
=23.
Answer:
The dimensions of the rectangular box, x = y = z = 0.817 cm
Step-by-step explanation:
Given;
total surface area of the rectangular box or cuboid = 4 cm²
A rectangular box with largest volume is a cube.
The total surface area of a cube = 6 times square of one edge length.
Let the edge length = given dimensions, x, y, z
x = y = z
6x² = 4
x² = 4/6
Therefore, the dimensions of the rectangular box, x = y = z = 0.817 cm
From what I know this graph looks like that of a modulus function except it's shifted 1 unit to right and 1 unit below the origin.
So the original equation must be:
y = |x|
And the transformed equation (aka the equation if this graph) must be,
y+1 = |x| -1
y = |x| -2
Answer:
(1, -3)
Step-by-step explanation:
Start where the axes meet. That is the origin (0,)
Move 1 place to the right that is the x coordinate
Move 3 places down that is the y coordinate
(1,-3)
Answer:
8 with a remainder of 4
step by step explanation:
