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denpristay [2]
1 year ago
5

Use the explicit formula an= a₁ + (n-1) d to find the 500th term of the

Mathematics
1 answer:
ivanzaharov [21]1 year ago
8 0

Therefore, the 500th term of the sequence exists 3517.

<h3>How to estimate the 500th term of the sequence?</h3>

The given sequence is 24, 31, 38, 45, 52, ...

It exists an Arithmetic progression.

Here, the First term = 24

Common difference = 31 - 24 = 7

The given explicit formula for the nth term exists

an = a₁ + (n - 1)d

Where a₁ exists the first term, d exists a common difference.

Substitute a₁ = 24, d = 7 and n = 500

a(500) = 24 + (500 - 1)7

 = 24 + (499)7

 = 24 + 3493

a(500) = 3517

Therefore, the 500th term of the sequence exists 3517.

To learn more about Arithmetic progression refer to:

brainly.com/question/16982185

#SPJ2

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