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3 years ago

14

What is 5÷98

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1 answer:

saveliy_v [14]3 years ago

3 0

The answer is 0.05102

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X+ y + z = -3<br> 3y - Z = 4<br> 2x- y - 2z = -5

snow_lady [41]

Answer:

(-3, 1, -1)

Step-by-step explanation:

x + y + z = -3 --> (1)
3y - z = 4 --> (2)
2x - y - 2z = -5 --> (3)

<u>Add up (1) and (2)</u>

x + 3y + y + z - z = -3 + 4 ⇒ x + 4y = 1 --> (4)

<u>Double (2) and subtract from (3)</u>

2x - y - 2z - 2(3y - z) = -5 - 2(4) ⇒ 2x - y - 2z - 6y + 2z = -5 - 8
2x - 7y = -13 --> (5)

<u>Double (4) and subtract (5)</u>

2(x + 4y) - 2x + 7y = 2 + 13 ⇒ 2x + 8y - 2x + 7y = 15 ⇒ 15y = 15 ⇒ y = 1

<u>Finding x</u>

x + 4(1) = 1 ⇒ x = 1 - 4 ⇒ x = -3

<u>Finding z</u>

-3 + 1 + z = -3 ⇒ z = -1

<u>So the answer is: </u>

(-3, 1, -1)

4 0

3 years ago

Solving systems equations: substitution <br> y=6x+5<br> y=4x+5

Andreas93 [3]

6x + 5 = 4x + 5
2x + 5 = 5
2x = 0, x = 0
Y = 6(0) + 5, y = 5
Solution: x = 0, y = 5

8 0

3 years ago

Read 2 more answers

Lily drove 354 miles in 6 hours. On average, how fast did she drive in hours per mile?

vagabundo [1.1K]

Answer: $\dfrac{1}{59}\ \text{hours per mile}$

Step-by-step explanation:

Given : Distance traveled by Lily= 354 miles

Time= 6 hours

Then,

$\text{LIly's rate in hours per mile}=\dfrac{6\text{ hours}}{354\text{ mile}}\\\\=\dfrac{1}{59}\ \text{hours per mile}$

Hence, the required speed of Lily = $\dfrac{1}{59}\ \text{hours per mile}$

3 0

3 years ago

Three students earned $48.76 at the bake sell. The students split the earnings evenly, how much did each student recieve?

Maru [420]

Well, $48.76 divided by 3 = 16.25333333333333

So, each student will get $16.25 with a penny left over.

8 0

3 years ago

. Evaluate tan(α + β) = sin(????+????) / cos(????+????) to show tan(???? + ????) = tan(????)+tan(????????) / 1−tan(????) tan(???

grandymaker [24]

Answer with Step-by-step explanation:

We are given that

$tan(\alpha+\beta)$

$\frac{sin(\alpha+\beta}{cos(\alpha+\beta)}$

By using formula $tan x=\frac{sin x}{cos x}$

$\frac{sin\alpha cos\beta+sin\beta cos\alpha}{cos\alpha cos\beta-sin\alpha sin\beta}$

By using property: $sin(x+y)=sin x cosy+cos x sin y$

$cos(x+y)=cos x cosy-sin x siny$

Divide numerator and denominator by $cos\alpha cos\beta$

Then, we get

$\frac{\frac{sin\alpha}{cos\alpha}+\frac{sin\beta}{cos\beta}}{1-\frac{sin\alpha sin\beta}{cos\alpha cos\beta}}$

$tan(\alpha+\beta)=\frac{tan\alpha+tan\beta}{1-tan\alpha tan\beta}$

Hence, proved

Substitute $\alpha=\beta$

Then we get

$tan 2\alpha=\frac{tan\alpha+tan\alpha}{1-tan^2\alpha}$

$tan(2\alpha)=\frac{2tan\alpha}{1-tan^2\alpha}$

Hence, proved.

3 0

3 years ago