The diameter of a coin is 22 millimeters

By talking to the sales clerk at the hardware store, you find out that the burglar has two hideouts — the lake house and the cab

DaniilM [7]

Cabin is your answer

3 0

3 years ago

2. What is the measure of angle AOE and angle EOD? X+138 x + 48

horrorfan [7]

Answer:

AOE = 138, EOD = 48

Step-by-step explanation:

Since AD is the diameter of the circle and goes through the middle

angle AOE + angle EOD = 180

Solving the equation (x + 138) + ( x+ 48) = 180

We get x = 0.

8 0

3 years ago

In 1995, Hazel was 25 years older than her son Gary. In 2022, Hazel's age will be 150% of Gary's age. How old were they in 1995?

Kitty [74]

So find the difference between 1995 and 2022 to make it easier
2022-1995=27

so the rephrased question is
when hazel was x years old, she was 25 years older than son gary who was y old at that time (equation is x is 25 more than y or x=25+y)
in 27 years, (this means x+27 and y+27) hazel's age will be 150% of gary's age (x+27= 150% of y+27)
percent means parts out of 100 so 150%=150/100=15/10=1.5
'of' in math means multiply so
the equations are
x=25+y
x+27=1.5(y+27)
subsitute 25+y for x in second euation
25+y+27=1.5(y+27)
add like terms
y+52=1.5(y+27)
I personally dislike decimals to multiply both sides by 2 to make 2 0.5's or 1 (you are technically supposed to distribute or divide both sides by 1.5) so
2y+104=3(y+27)
distribute
2y+104=3y+81
subtract 2y from both sides
104=y+81
subtract 81 from both sides
23=y
subsitute
x=25+y
x=25+23
x=48

Hazel was 48 and Gary was 23 in the year of 1995

5 0

3 years ago

If we place all the rational numbers on a number line, how close are the numbers? That is to say, what is the distance between o

satela [25.4K]

the distance that we would have if we made the line of centimeters the distance would be 1mm, if we did it in decimeter, the distance would be 1cm and then successively.

3 0

3 years ago

4. Professor Kingsfield's class follows very strict grading guidelines. Assume that student averages in Kingsfield's class are n

gtnhenbr [62]

Answer:

For grade A ,a student needs Z score of 2 or above, the required score is

X = 68 + 12Z =92, For grade B, a student needs Z score between 1 and 2 .

The required score is = 68 + (12 * 1) < X = 68 + ( 12 * 2) = 80 < X < 92, For grade C ,a student needs Z score between -1 and 1 . The required score is = 68 + ( 12 * x - 1) < X = 68 + (12 * x 1) = 56 <X<80. For the grade D, a student needs Z score between -2 and -1 .

The required score is = 68 + (12 * x -2) < X = 68 + (12 * x -1) = 44< X< 56

Step-by-step explanation:

From the given question,

let the rv X represent student's score.

Z = x - 68/12 ~ N (0,1 )

Now, we know for a standard normal distribution

Thus,

For grade A ,a student needs Z score of 2 or above, the required score is

X = 68 + 12Z =92

For grade B, a student needs Z score between 1 and 2 .

The required score is = 68 + (12 * 1) < X = 68 + ( 12 * 2) = 80 < X < 92

For grade C ,a student needs Z score between -1 and 1 .

The required score is = 68 + ( 12 * x - 1) < X = 68 + (12 * x 1) = 56 <X<80

For the grade D, a student needs Z score between -2 and -1 .

The required score is = 68 + (12 * x -2) < X = 68 + (12 * x -1) = 44< X< 56

For student with score less 44 gets an F.

Note: find an attached image for the graphic sketch of the normal distribution.

3 0

4 years ago