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3 years ago

4/? = ?/ 9

Mathematics

1 answer:

svet-max [94.6K]3 years ago

3 0

Set ? as x, and cross-multiply.

so x^2= 36

x = 6 or x = -6

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It would be -15m + -20

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3 years ago

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A scooter can travel 72 mi per gallon of gasoline and holds 2.3 gal. the function d(x)-72x represents the distance d(x), in mile

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The scooter can go 165.6 miles

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3 years ago

The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e

marusya05 [52]

Answer:

The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:

$\hat p =\frac{955-812}{955}= 0.150$

$0.150 - 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.131$

$0.150 + 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.169$

And the 90% confidence interval would be given (0.131;0.169).

Step-by-step explanation:

We have the following info given:

$n= 955$ represent the sampel size slected

$x = 812$ number of students who read above the eighth grade level

The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:

$\hat p =\frac{955-812}{955}= 0.150$

The confidence interval for the proportion would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 90% confidence interval the significance is $\alpha=1-0.9=0.1$ and $\alpha/2=0.05$ , with that value we can find the quantile required for the interval in the normal standard distribution and we got.

$z_{\alpha/2}=1.64$

And replacing into the confidence interval formula we got:

$0.150 - 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.131$

$0.150 + 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.169$

And the 90% confidence interval would be given (0.131;0.169).

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3 years ago

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12345 [234]

Answer:

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Step-by-step explanation:

To solve, you can simply list the square numbers in order...

1^2, 2^2, 3^2, 4^2, 5^2, 6^2, 7^2.

1, 4, 9, 16, 25, 36, 49.

Hope this helps!

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goblinko [34]

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2 years ago