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2 years ago

N fewer carrots than 12

1 answer:

8 0

Its simple (n-12) because n is the variable and since it says fewer, then that means less than, which is subtracted by the number given which would be 12. Hope this helps! XD

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A parking space shaped like a parallelogram has a base of 17 feet and a height of 9 feet if a mini car 6 feet long and five feet

lesantik [10]

Answer:

123 cm²

Step-by-step explanation:

First of all, we need to know how exactly to find the area of a parallelogram.

Area of parallelogram= Base*Height

PARALLELOGRAM-

BASE= 17 ft

HEIGHT= 9ft

AREA= 17*9= 153 cm²

The area of parallelogram, will be considered as WHOLE AREA.

Now,

AREA OF MINI CAR-

length= 6 ft

Width= 5 ft

Area= 6*5= 30 ft ²

Square feet uncovere-

153 ft²- 30 ft²= 123 ft²

HOPE IT HELPS!

8 0

2 years ago

A -76x+76=-76x+76−76x+76=−76x+76minus, 76, x, plus, 76, equals, minus, 76, x, plus, 76 (Choice B) B 76x+76=-76x+7676x+76=−76x+76

Pie

Answer:

Step-by-step explanation:

i could be wrong

5 0

3 years ago

There are 5 white roses to every 9 red roses in the garden

KiRa [710]

Answer:

Step-by-step explanation:

ummm what there is no question!

5 0

2 years ago

Ron started the day with a score of +12.

Naily [24]

+ 12 - 4 + 3 - 15

= 12 + 3 - 4 - 15

= 15 - 19

= - 4

8 0

2 years ago

Read 2 more answers

An advertising company designs a campaign to introduce a new product to a metropolitan area of population 3 Million people. Let

Advocard [28]

Answer:

$P(t)=3,000,000-3,000,000e^{0.0138t}$

Step-by-step explanation:

Since P(t) increases at a rate proportional to the number of people still unaware of the product, we have

$P'(t)=K(3,000,000-P(t))$

Since no one was aware of the product at the beginning of the campaign and 50% of the people were aware of the product after 50 days of advertising

P(0) = 0 and P(50) = 1,500,000

We have and ordinary differential equation of first order that we can write

$P'(t)+KP(t)= 3,000,000K$

The integrating factor is

$e^{Kt}$

Multiplying both sides of the equation by the integrating factor

$e^{Kt}P'(t)+e^{Kt}KP(t)= e^{Kt}3,000,000*K$

Hence

$(e^{Kt}P(t))'=3,000,000Ke^{Kt}$

Integrating both sides

$e^{Kt}P(t)=3,000,000K \int e^{Kt}dt +C$

$e^{Kt}P(t)=3,000,000K(\frac{e^{Kt}}{K})+C$

$P(t)=3,000,000+Ce^{-Kt}$

But P(0) = 0, so C = -3,000,000

and P(50) = 1,500,000

$e^{-50K}=\frac{1}{2}\Rightarrow K=-\frac{log(0.5)}{50}=0.0138$

And the equation that models the number of people (in millions) who become aware of the product by time t is

$P(t)=3,000,000-3,000,000e^{0.0138t}$

5 0

3 years ago