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tensa zangetsu [6.8K]
4 years ago
13

Can somebody help please

Mathematics
1 answer:
Alexxx [7]4 years ago
7 0

Answer:

D.

Step-by-step explanation:

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Anni [7]

\frac{2}{6}

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3 years ago
Chantal cut an apple into a equal slices. She ate 4 slices and had 4 slices left. Which equation models the problem?
Citrus2011 [14]
So equal slices
total=x
she ate 4 slices from x so -4
x-4
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8 0
3 years ago
Please can u help simplify
Triss [41]

Answer:

frac{21x^6y^5}{14x^2y^9}

Factor the number =\frac{7\cdot \:3x^6y^5}{14x^2y^9}

Factor the number 14=7. 2 =\frac{7\cdot \:3x^6y^5}{7\cdot \:2x^2y^9}

Cancel\:the\:common\:factor:}\:7 =\frac{3x^6y^5}{2x^2y^9}

Step-by-step explanation:

4 0
3 years ago
Write a division problem that will have a 2 digit quotient and another division problem that will have a 3 digit quotient. Expla
o-na [289]

Answer:

\frac{240}{4} =60

\frac{1800}{3} =600

Step-by-step explanation:

1.  The result should by a 2 digit number.

So, I fix a two digit number first, say 60.

Then, I multiplied it by some random integer, say 4 and got 240.

Now, 240 is my dividend and 4 is my divisor.

My division problem is:

\frac{240}{4} =60


2.  The result should be a 3 digit number.

So, I fix a three digit number first, say 600.

Then, I multiplied it by some random integer, say 3 and got 1800.

Now, 1800 is my dividend and 3 is my divisor.

My division problem is:

\frac{1800}{3} =600

6 0
4 years ago
Read 2 more answers
g A coin where the probability of heads is 0.3 is flipped 2000 times. Use the normal approximation to the binomial distribution
matrenka [14]

Title:

<h2>See the explanation.</h2>

Step-by-step explanation:

The coin is to be flipped 2000 times.

The probability of getting a head is 0.3.

It is given that, we need to get a head in between 575 and 618 times.

If we will get 575 heads then we will get (2000 - 575) tails.

Hence, if we take that we want to get n times head, then we will get (2000 - n) times tail.

The probability of not getting a head is (1 - 0.3) = 0.7.

The probability of getting n times head is ^{2000}C_n (0.3)^n \times (0.7)^{2000 - n}.

The required probability is ∑ ^{2000}C_n (0.3)^n \times (0.7)^{2000 - n}, where 575 \leq n \leq 618.

5 0
3 years ago
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