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seropon [69]
4 years ago
15

A taxi service charges an initial fee plus $1.80 per mile. How far can you travel for $12

Mathematics
1 answer:
adoni [48]4 years ago
8 0
X= initial fee
m= per mile

x+1.80m=12
this is your equation

hope this helps
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17. Solve for p in the equation 7p = –63.
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It’s A

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Suppose the baker has 4 loafs of bread and cuts the loafs into halves.how many 1/2 pound loaves of bread would the baker have?
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Write the related series for the finite sequence 3, 7, 11, ..., 27. Then find the sum
sweet [91]

Answer:

The sum =105

Step-by-step explanation:

It is given that, finite sequence 3, 7, 11, ..., 27.

<u>Points to remember</u>

1). For a finite sequence sum of n term is given by

Sum  = n/2[first term + last term]

2). nth term of of an AP

tₙ = a + (n - 1)d

Where a - First term

d - common difference

<u>To find the number of terms in the given sequence</u>

Here a = 3 and d = 7 - 3 = 4

tₙ = a + (n - 1)d

27  = 3 + (n - 1)*4

4(n -1) = 27 - 3 = 24

n - 1 = 24/4 = 6

n = 6 +1 =7

<u>To find the sum</u>

Sum  = n/2[first term + last term]

 = 7/2[3 + 27]

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8 0
3 years ago
1 2/3- (-5 2/5)+000000?
kondaur [170]
<h2>The value of 1\dfrac{2}{3}-(-5\dfrac{2}{5} )+000000 = \dfrac{106}{15} or, 7\dfrac{1}{15}</h2>

Step-by-step explanation:

We have,

1\dfrac{2}{3}-(-5\dfrac{2}{5} )+000000

To find, 1\dfrac{2}{3}-(-5\dfrac{2}{5} )+000000 = ?

∴ 1\dfrac{2}{3}-(-5\dfrac{2}{5}) +000000

= 1 + \dfrac{2}{3} + 5\dfrac{2}{5}

=1+\dfrac{2}{3}+5+\dfrac{2}{5}

= (1 + 5) + (\dfrac{2}{3}+\dfrac{2}{5})

= (1 + 5) + \dfrac{10+6}{15}

= 6 + \dfrac{16}{15}

= \dfrac{90+16}{15}

= \dfrac{106}{15}

= 7\dfrac{1}{15}

Thus, the value of 1\dfrac{2}{3}-(-5\dfrac{2}{5} )+000000 = \dfrac{106}{15} or, 7\dfrac{1}{15}

8 0
3 years ago
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