1) What is the shape of the graph of the following parametric equations?
1 answer:
Answer:
The shape of the graph of the parametric equations given is:
- <u>B. ellipse</u>.
Step-by-step explanation:
By inserting each of the equations given in a graphing calculator (Annex 1), it can be identified that both the first and second equations have an elliptical or ellipse shape, which is characterized by being periodic in the two directions in which it runs. Thus, the equation x = 3 cos t runs with elliptical motion on the Y-axis of the Cartesian plane, while the equation y = 2 without t + 1 runs with elliptical motion on the X-axis.
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Given statement is "point where the perpendicular bisectors of the three sides of a triangle intersect".
Perpendicular is basically a vertical line that makes 90 degree angle with the base.
bisector means the line which divides side into two equal parts.
So perpendicular bisector in any triangle will be the line which is drawn on the side of the triangle and perpendicular to that side.
Now these perpendicular bisectors meet at some point.
That point is called circumcenter.
Hence final answer will be "circumcenter".
Answer:
C
Step-by-step explanation:
= 6 ( multiply both sides by 3x to clear the fraction )
15y - 10 = 18x ( add 10 to both sides )
15y = 18x + 10 ( divide terms by 15 )
y = x +
, that is
y = x +
→ C