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3 years ago

-18-3 what's the answer

2 answers:

6 0

It's just simple subtraction. The answer is -21.

*Tip: I method I like to use is, when both numbers are negative, just add them and add the negative sign.

Hope I helped! <3

Llana [10]3 years ago

4 0

The answer is -21. Rule is that you follow the sign of the larger and add the opposite

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Match each set of vertices with the type of quadrilateral they form.

Serjik [45]

Only correct the first one.

Please, see the graph in the attached file.

1) a rectangle with    A(3,3), B(3,6),
noncongruent ←→ C(7,6), D(7,3)
adjacent sides
(in green)

2) a parallelogram
with A(2,0), B(3,2)
nonperpendicular ←→ C(6,3), D(5,1)
adjacent sides
(in blue)

3) a square ←→ A(3,3), B(2,5),
(in red) C(4,6), D(5,4)

4) a rhombus with       A(2,-2), B(3,0),
nonperpendicular    ←→ C(4,-2), D(3,-4)
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5 0

4 years ago

I need help on doing this

Rudik [331]

Answer:

#5A=6

5B=4

Step-by-step explanation:

7 0

3 years ago

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24. Find the area of the shaded region:

Monica [59]

Answer:

A = 5x³ + 17x² - 35x - 30

Step-by-step explanation:

the shaded area (A) is calculated as

A = outer area - inner area

= (5x + 3)(x² + 4x - 10) - 3x(2x - 1) ← distribute parenthesis

= 5x³ + 20x² - 50x + 3x² + 12x - 30 - (6x² - 3x)

= 5x³ + 23x² - 38x - 30 - 6x² + 3x ← collect like terms

= 5x³ + 17x² - 35x - 30

7 0

2 years ago

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Round decimals <br> Write the place value of the underline digit

atroni [7]

So all you have to do is look at were the number is is it is in the first spot it is in the tenths place value, second spot hundredth and so

6 0

3 years ago

If a single card is drawn from a standard 52-card deck, what is the probability that it is an ace or a spade?

klasskru [66]

A 52-card deck is made up of an equal number of diamonds, hearts, spades, and clubs. Because there are 4 suits, there is a 1/4 chance to draw one of them, in our case, spades.

There are 4 aces in a 52-card deck, so the chance of drawing one is 4/52, or 1/13.

The question asks for the probability of drawing an ace or a spade. Because it uses the word "or," we add the probabilities together. This is because there is a chance of drawing either of the cards; it doesn't have to meet both requirements to satisfy the statement.

However, if the question were to say "and," we would multiply the two probabilities.

Let's add 1/4 and 1/13. First, we can find a common denominator. We can use 52 because both fractions can multiply into it (since the ratio came from a deck of 52 cards as well).

$\frac{1}{4} -- > \frac{13}{52}$

$\frac{1}{13} -- > \frac{4}{52}$

Now we can add them together.

$\frac{13}{52} + \frac{4}{52} = \frac{13+4}{52} = \frac{17}{52}$

This cannot be simplified further, so the probability is 17 in 52, or 33%.

hope this helps!

7 0

1 year ago

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