Dominic spent 2 3/4 hours on art project. Rachel worked 1 1/3 times as long. How many hours did Rachel work for?

2 answers:

4 0

Rachel worked for 3 2/3 hours.

Multiply the fractions to get the answer.

2 3/4 x 1 1 /3 is 3 2/3.

Hope it helps you :D

N76 [4]2 years ago

3 0

3 and 2/3 hours.

Multiply the number of hours Dominic spent by the scale factor.

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Jaylen earns $4250 each month at his job. At this rate, how much will he

dezoksy [38]

Answer:

Step-by-step explanation:

<h2>18 months in 1 $\frac{1}{2}$ years.</h2><h2>4250 x 18 = 76,500</h2>

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1 year ago

WHAT IS THE PRODUCT OF: 7.21 x 4.2<br> PLEASE--

lesantik [10]

<h3><u>QU</u><u>ESTION</u><u>:</u></h3>

WHAT IS THE PRODUCT OF: 7.21 x 4.2

PLEASE--

<h3>SOLUTION AND ANSWER:</h3>

$\: \: \: \: \sf7.2 \: 1 \\ \sf \times \: \: \: \: 4.2 \\ \: \: \sf \overline{1 \: 4 \: 4 \: 2} \\ \sf + \: 2 \: 8 \: 8 \: 4 \: 0 \: \: \: \: \: \\ \sf \overline{ \orange{3 \: 0.2 \: 8 \: 2}}$

THEREFORE, <em><u>30.282</u></em> IS THE PRODUCT

HOPE THIS HELP YOU! HAVE A NICE DAY!

~kimtaetae92~

NOTE: Kindly see this answer from brainly app if you are in web to see the displayed formats here.

7 0

2 years ago

write the equation of a line that is perpendicular to the given line and that passes through the given point. y-4=5/2(x+3) ; (-7

faltersainse [42]

The gradient of the perpendicular line would be the negative reciprocal of the original line. Therefore the gradient of the perpendicular line would be -2/5x.
Since we know y=mx+c, ∴y=-2/5x+c. Sub in the x and y values of the given point and we get that c=26/5.

The perpendicular equation would be y=-2/5x+26/5.
I hope I got this right.

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3 years ago

Read 2 more answers

A 20-foot cable hangs from the top of a building that is 50 feet high. if the cable weighs 2 pounds per foot, how much work is d

pychu [463]

20*2=40
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4 0

2 years ago

Help Would Be Appreciated!

ycow [4]

With an equation you must isolate x or whatever the variable is. Operations are the things used to make the difference like +,-,x,/.

A great example of this is the following