I think the graph below is correct.
Answer:
Yes, △ABC ∼ △FED by AA postulate.
Step-by-step explanation:
Given:
Two triangles ABC and FED.
m∠A = m∠B
m∠C = m∠A + 30°
m∠E = m∠F = 
m∠D =
°.
Now, let m∠A = m∠B = 
So, m∠C = m∠A + 30° = 
Now, sum of all interior angles of a triangle is 180°. Therefore,
m∠A + m∠B + m∠C = 180

Therefore, m∠A = 50°, m∠B = 50° and m∠C = m∠A + 30° = 50 + 30 = 80°.
Now, consider triangle FED,
m∠D+ m∠E + m∠F = 180

Therefore, m∠F = 50°
m∠E = 50° and
m∠D = 
So, both the triangles have congruent corresponding angle measures.
m∠A = m∠F = 50°
m∠B = m∠E = 50°
m∠C = m∠D = 80°
Therefore, the two triangles are similar by AA postulate.
Answer:
The answer is x≤-4/7
Step-by-step explanation:
hope thia helps
Brainliest????
C = Pi * d where C = circumference, d = diameter, r = radius
C = 2*pi *r
we need to watch the units since they are different
Pool A
C = 2 * pi * r
C = 2 * pi * 12 = 24 * pi in feet
Pool B
C = pi * d
change meters to feet
7.5 m * 3.28 ft/ 1 m = 24.6 ft
C = pi * 24.6 = 24.6* pi in ft
Pool B had a greater circumference
24.6 * pi > 24 pi