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seropon [69]
3 years ago
15

There are several different methods for finding the slope of a line depending on the information given. In your own words, pleas

e describe one method for finding slope and provide an example for using said method.
Mathematics
1 answer:
kari74 [83]3 years ago
4 0
Slope of the line can be found using 2 points on a line. the equation y2 - y1 / x2 - x1 can be used to find slope. for example, find the slope of a line that passes through (1,2) and (2,4)

4-2 / 2-1 = 2/1 = 2
the slope is 2
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Plzz help <br><br>find value of following : 2sin75°.cos15°​
polet [3.4K]

Answer:

\frac{2+\sqrt{3} }{2}

Step-by-step explanation:

Using the product to sum formula

sinxcosy = \frac{1}{2} [ sin(x + y) + sin(x - y) ] , then

2sinxcosy = sin(x + y) + sin(x - y)

Given

2sin75°cos15° ← with x = 75 and y = 15 , then

= sin(75 + 15) + sin(75 - 15)

= sin90° + sin60°

= 1 + \frac{\sqrt{3} }{2}

= \frac{2+\sqrt{3} }{2}

6 0
3 years ago
Write any Quetion of of line through the given points. (-3,-2) (-1,-6)
ArbitrLikvidat [17]
What is the starting point?
5 0
4 years ago
1) Give an equation for the line which goes through (1,-5) and has slope m=-3.
defon

Answer:

y=-3x-2

Step-by-step explanation:

Using y-y_1=m(x-x_1):

         y--5=-3(x-1)

               ⇒ y=-3x-2

7 0
2 years ago
Use Pascal's triangle to expand the binomial.
KatRina [158]

Answer:

(d - 5)^6 = d^6 - 30*d^5 + 375*d^4 - 2500*d^3 + 9375*d^2 - 18750*d + 15625

Step-by-step explanation:

Suppose you have (x + y)^6, the numbers  in the 6th row of Pascal's triangle are the coefficients of the terms in a sixth order polynomial.

In the figure attached, Pascal's triangle is shown.

The coefficients are 1, 6, 15, 20, 15, 6,1. Then:

(x + y)^6 =  x^6 + 6*x^5*y + 15*x^4*y^2 + 20*x^3*y^3 + 15*x^2*y^4 + 6*x*y^5+ y^6

Replacing x = d and y = -5:

(d - 5)^6 =  d^6 + 6*d^5*(-5) + 15*d^4*(-5)^2 + 20*d^3*(-5)^3 + 15*d^2*(-5)^4 + 6*d*(-5)^5+ (-5)^6

(d - 5)^6 = d^6 - 30*d^5 + 375*d^4 - 2500*d^3 + 9375*d^2 - 18750*d + 15625

7 0
3 years ago
Read 2 more answers
What are the solution(s) of –x2 + 2x + 3 = x2 – 2x + 3?
Leviafan [203]
-x^2+2x+3=x^2-2x+3  add x^2 to both sides

2x+3=2x^2-2x+3  subtract 2x from both sides

3=2x^2-4x+3  subtract 3 from both sides

2x^2-4x=0  factor

2x(x-2)=0

So x=0 and 2
3 0
3 years ago
Read 2 more answers
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