Answer:
Step-by-step explanation:
A binary string with 2n+1 number of zeros, then you can get a binary string with 2n(+1)+1 = 2n+3 number of zeros either by adding 2 zeros or 2 1's at any of the available 2n+2 positions. Way of making each of these two choices are (2n+2)22. So, basically if b2n+12n+1 is the number of binary string with 2n+1 zeros then your
b2n+32n+3 = 2 (2n+2)22 b2n+12n+1
your second case is basically the fact that if you have string of length n ending with zero than you can the string of length n+1 ending with zero by:
1. Either placing a 1 in available n places (because you can't place it at the end)
2. or by placing a zero in available n+1 places.
0 ϵ P
x ϵ P → 1x ϵ P , x1 ϵ P
x' ϵ P,x'' ϵ P → xx'x''ϵ P
Answer:
ummmm is it meant to ask in 2 years instead of into years? if so
36/99 because 36 divided by 99 is 0.363636363636
The associative property of real numbers is shown in the number expression 3 + ((-5) + 6) = (3 + (-5)) + 6
<h3>What is an arithmetic operation?</h3>
It is defined as the operation in which we do the addition of numbers, subtraction, multiplication, and division. It has a basic four operators that is +, -, ×, and ÷.
We have a number expression:
= 3 + ((-5) + 6) = (3 + (-5)) + 6
As we know in the associative property:
a + (b + c) = (a + b) + c
= (3 + (-5)) + 6
Thus, the associative property of real numbers is shown in the number expression 3 + ((-5) + 6) = (3 + (-5)) + 6
Learn more about the arithmetic operation here:
brainly.com/question/20595275
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Given parameters;
Let us solve this problem step by step;
Let us represent Simon's money by S
Kande's money by K
- Simon has more money than Kande
S > K
- if Simon gave Kande K20, they would have the same amount;
if Simon gives $20, his money will be S - 20 lesser;
When Kande receives $20, his money will increase to K + 20
S - 20 = K + 20 ------ (i)
- While if Kande gave Simon $22, Simon would then have twice as much as Kande;
if Kande gave Simon $22, his money will be K - 22
Simon's money, S + 22;
S + 22 = 2(K - 22) ------ (ii)
Now we have set up two equations, let us solve;
S - 20 = K + 20 ---- i
S + 22 = 2(K - 22) ; S + 22 = 2K - 44 ---- ii
So, S - 20 = K + 20
S + 22 = 2K - 44
subtract both equations;
-20 - 22 = (k -2k) + 64
-42 = -k + 64
k = 106
Using equation i, let us find S;
S - 20 = K + 20
S - 20 = 106 + 20
S = 106 + 20 + 20 = 146
Therefore, Kande has $106 and Simon has $146
