All categories

3 years ago

We can define a propration as

Mathematics

2 answers:

coldgirl [10]3 years ago

7 0

Comparative relationships between numbers

Masja [62]3 years ago

4 0

A porporation is a comparative relationship to a whole

You might be interested in

Consider the two dot plots below.

Ann [662]

Answer:

the answer is D: the median of both the dot plot A and B is the same

Step-by-step explanation:

median is the middle value; after arranging the data in ascending or descending order...the mean of the two values is an even # of values

The median of dot plot A and median of dot plot B is 5; so therefore, the pots A and B are the same.

7 0

3 years ago

Using the graphing function on your calculator, what is the solution to the system of equations shown below?

SpyIntel [72]

Answer:
B, x=3 y=5

Step-by-step explanation:
x=-7+2y
3y+2x=21
Substitute the x into the other equation
3y+2(-7+2y)=21
y=5
Now put the value into a desired equation
x=-7+2(5)
x=3.
The answer is x=3 and y=5

I hope this helped!

5 0

4 years ago

HELP PLEASE I REALLY NEED IT

dangina [55]

Answer:

1.5

Step-by-step explanation:

5 0

3 years ago

Solve the equation using the substitution u = y/x. When u = y/x is substituted into the equation, the equation becomes separable

bekas [8.4K]

Answer:

$\frac{u^2+3}{-u^3+u^2-2u}u'=\frac{1}{x}$

Step-by-step explanation:

First step: I'm going to solve our substitution for y:

$u=\frac{y}{x}$

Multiply both sides by x:

$ux=y$

Second step: Differentiate the substitution:

$u'x+u=y'$

Third step: Plug in first and second step into the given equation dy/dx=f(x,y):

$u'x+u=\frac{x(ux)+(ux)^2}{3x^2+(ux)^2}$

$u'x+u=\frac{ux^2+u^2x^2}{3x^2+u^2x^2}$

We are going to simplify what we can.

Every term in the fraction on the right hand side of equation contains a factor of $x^2$ so I'm going to divide top and bottom by $x^2$ :

$u'x+u=\frac{u+u^2}{3+u^2}$

Now I have no idea what your left hand side is suppose to look like but I'm going to keep going here:

Subtract u on both sides:

$u'x=\frac{u+u^2}{3+u^2}-u$

Find a common denominator: Multiply second term on right hand side by $\frac{3+u^2}{3+u^2}$ :

$u'x=\frac{u+u^2}{3+u^2}-\frac{u(3+u^2)}{3+u^2}$

Combine fractions while also distributing u to terms in ( ):

$u'x=\frac{u+u^2-3u-u^3}{3+u^2}$

$u'x=\frac{-u^3+u^2-2u}{3+u^2}$

Third step: I'm going to separate the variables:

Multiply both sides by the reciprocal of the right hand side fraction.

$u' \frac{3+u^2}{-u^3+u^2-2u}x=1$

Divide both sides by x:

$\frac{3+u^2}{-u^3+u^2-2u}u'=\frac{1}{x}$

Reorder the top a little of left hand side using the commutative property for addition:

$\frac{u^2+3}{-u^3+u^2-2u}u'=\frac{1}{x}$

The expression on left hand side almost matches your expression but not quite so something seems a little off.

5 0

3 years ago

Write the equation of the line that passes

grandymaker [24]

Answer:

y=2x+2

Step-by-step explanation:

The equation will be y=2x+b. Note the slope is 2, since this line is parallel to y=2x+14.

Substitute (2,6) in it and we get 6=2(2)+b

6=4+b

b=2

So y=2x+2

5 0

3 years ago