Answer:
The length and width of the parking lot is 78 meters and 114 meters respectively.
Step-by-step explanation:
Given;
Perimeter of the parking lot =
Solution,
Let the width of the parking lot be x.
Then, according to question length = (x-36).
The perimeter of a rectangle is sum of all the sides of rectangle. Which is given by an expression;
Now substituting the values, we get;
Width =
Length =
Hence the length and width of the parking lot is 78 meters and 114 meters respectively.
5x-8y=1...(1)
3x+6y=-21...(2)
(1)*3:
15x-24y=3...(3)
(2)*5:
15x+30y=-105...(2)
(3)-(2):
15x-24y-(15x+30y)=3-(-105)
15x-24y-15x-30y=108
-54y=108
y=-2
Answer:
676
Step-by-step explanation:
d1×d2/2
42×56/2
1352/2=676
please check it by doing again
Angle ABG because ABG+ABE= 180