solve p varies directly as the square of s and inversely as r, when s=6,r=3,and p=48 find the value of p when s =10and r=5
1 answer:
Answer:
see explanation
Step-by-step explanation:
Given that p varies directly as s² and inversely as r then the equation relating them is
p = ← k is the constant of variation
To find k use the condition when s = 6, r = 3 and p = 48, that is
48 = ( multiply both sides by 3 to clear the fraction
144 = 36k ( divide both sides by 36 )
4 = k , thus
p = ← equation of variation
When s = 10 and r = 5 , then
p = =
= 80
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Answer:
The equation of the sraight line 3x- y+ 6 =0
Step-by-step explanation:
<u><em>Explanation:-</em></u>
Given that the gradient of the function
|gradf| = 3 and point (-1,3)
Given that the slope of the line
m = 3
The equation of the straight line passing through the point(-1,3) and slope m =3
y-3 = 3(x-(-1))
y-3 = 3x+3
3x +3-y+3=0
3x- y+ 6 =0
<u><em>Final answer:-</em></u>
The equation of the sraight line 3x- y+ 6 =0
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Answer: Probability that students who did not attend the class on Fridays given that they passed the course is 0.043.
Step-by-step explanation:
Since we have given that
Probability that students attend class on Fridays = 70% = 0.7
Probability that who went to class on Fridays would pass the course = 95% = 0.95
Probability that who did not go to class on Fridays would passed the course = 10% = 0.10
Let A be the event students passed the course.
Let E be the event that students attend the class on Fridays.
Let F be the event that students who did not attend the class on Fridays.
Here, P(E) = 0.70 and P(F) = 1-0.70 = 0.30
P(A|E) = 0.95, P(A|F) = 0.10
We need to find the probability that they did not attend on Fridays.
We would use "Bayes theorem":
Hence, probability that students who did not attend the class on Fridays given that they passed the course is 0.043.