Question

solve p varies directly as the square of s and inversely as r, when s=6,r=3,and p=48 find the value of p when s =10and r=5​

Answer 1

Answer:

see explanation

Step-by-step explanation:

Given that p varies directly as s² and inversely as r then the equation relating them is

p = $\frac{ks^2}{r}$ ← k is the constant of variation

To find k use the condition when s = 6, r = 3 and p = 48, that is

48 = $\frac{6^2k}{3}$ ( multiply both sides by 3 to clear the fraction

144 = 36k ( divide both sides by 36 )

4 = k , thus

p = $\frac{4s^2}{r}$ ← equation of variation

When s = 10 and r = 5 , then

p = $\frac{4(10)^2}{5}$ = $\frac{400}{5}$ = 80