Answer:
(a) 0.28347
(b) 0.36909
(c) 0.0039
(d) 0.9806
Step-by-step explanation:
Given information:
n=12
p = 20% = 0.2
q = 1-p = 1-0.2 = 0.8
Binomial formula:

(a) Exactly two will be drunken drivers.



Therefore, the probability that exactly two will be drunken drivers is 0.28347.
(b)Three or four will be drunken drivers.


Using binomial we get



Therefore, the probability that three or four will be drunken drivers is 0.3691.
(c)
At least 7 will be drunken drivers.

![P(x\leq 7)=1-[P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)+P(x=5)+P(x=6)]](https://tex.z-dn.net/?f=P%28x%5Cleq%207%29%3D1-%5BP%28x%3D0%29%2BP%28x%3D1%29%2BP%28x%3D2%29%2BP%28x%3D3%29%2BP%28x%3D4%29%2BP%28x%3D5%29%2BP%28x%3D6%29%5D)
![P(x\leq 7)=1-[0.06872+0.20616+0.28347+0.23622+0.13288+0.05315+0.0155]](https://tex.z-dn.net/?f=P%28x%5Cleq%207%29%3D1-%5B0.06872%2B0.20616%2B0.28347%2B0.23622%2B0.13288%2B0.05315%2B0.0155%5D)
![P(x\leq 7)=1-[0.9961]](https://tex.z-dn.net/?f=P%28x%5Cleq%207%29%3D1-%5B0.9961%5D)

Therefore, the probability of at least 7 will be drunken drivers is 0.0039.
(d) At most 5 will be drunken drivers.



Therefore, the probability of at most 5 will be drunken drivers is 0.9806.
Answer:
B) 3
Step-by-step explanation:
f(3) = 3^2 + 3(3) = 9 + 9 = 18
Hey!
Hope this helps...
~~~~~~~~~~~~~~~~~~~~~~~~~
Car #1: 300/43.2 = 6.9444 gallons
(Rounded) Car #2: 300/35.9 = 8.3565 gallons
~~~~~~~~~~~~~~~~~~~~~~~~~
(Rounded) Car #1: 6.9444*3.19 = $22.16 to re-fill their tank
(Rounded) Car #2: 8.3565*3.19 = $26.66 to re-fill their tank
~~~~~~~~~~~~~~~~~~~~~~~~~
(Rounded) Difference: $26.66 - 22.15 = $4.50
To re-fill Car 2's tank is approximately $4.50 more to re-fill Car 1's tank...
The son is 4 years old and the dad is 24 years old.
Answer:
Attached below
Step-by-step explanation:
sorry couldnt d it on paper ;)