1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
OverLord2011 [107]
3 years ago
8

Find

Mathematics
1 answer:
Westkost [7]3 years ago
8 0

Answer:

dy/dx = -b/a cot α

Step-by-step explanation:

x² / a² + y² / b² = 1

Take derivative with respect to x.

2x / a² + 2y / b² dy/dx = 0

2y / b² dy/dx = -2x / a²

dy/dx = -b²x / (a²y)

Substitute:

dy/dx = -b²a cos α / (a²b sin α)

dy/dx = -b cos α / (a sin α)

dy/dx = -b/a cot α

You might be interested in
In order to develop a more appealing​ cheeseburger, a franchise uses taste tests with 9 different​ buns, 8 different​ cheeses, 4
Nesterboy [21]

Answer:

8,640 minutes

Step-by-step explanation:

<em>Re-read the question:</em> "How long would it take the test to eat all possible cheeseburgers?"

<em>What are they asking for?</em>

Answer: Total time test all possible burgers

<em>We can break down the answer into a multiplication:</em>

Total time to test all possible burgers =

<u>Time to test each burger</u> x <u>Number of possible burgers</u>

A) Time to test each burger is given - 10 minutes.

B) Number of possible burgers is essentially the total number of combinations of toppings you can have. The order of toppings doesn't matter, so this problem is called a "Combination Problem," as opposed to a "Permutation Problem" which is a problem when order matters.

<em>How do we solve Combination problems? </em>

<em>Just multiply the quantity of each option.</em>

Number of combinations of burger toppings = # bun types x # cheese types x # lettuce types x # tomato types

Number of combinations of burger toppings = 9 x 8 x 4 x 3 = 864

<em>Now plug this into the original equation</em>

Total time to test all possible burgers

= time to test each burger x number of possible burgers

= 10 minutes x 864 possible options

= 8,640 minutes

7 0
4 years ago
) e number of viewers ordering a particular pay-per-view program is normally distributed. Past history shows that 33.00% of the
lubasha [3.4K]

Answer:

The mean of the number of people ordering the program is 22,046.5 and the standard deviation is 4,651.16.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Past history shows that 33.00% of the time fewer than 20,000 people order the program

This means that X = 20000 has a pvalue of 0.33. So when X = 20000, Z = -0.44.

Z = \frac{X - \mu}{\sigma}

-0.44 = \frac{20000 - \mu}{\sigma}

20000 - \mu = -0.44\sigma

\mu = 20000 + 0.44\sigma

Only ten percent of the time do more than 28,000 people order the program.

This means that X = 28000 has a pvalue of 1-0.1 = 0.9. So when X = 28000, Z = 1.28.

Z = \frac{X - \mu}{\sigma}

1.28 = \frac{28000 - \mu}{\sigma}

28000 - \mu = 1.28\sigma

\mu = 28000 - 1.28\sigma

Also

\mu = 20000 + 0.44\sigma

So

20000 + 0.44\sigma = 28000 - 1.28\sigma

1.72\sigma = 8000

\sigma = \frac{8000}{1.72}

\sigma = 4651.16

\mu = 20000 + 0.44\sigma = 20000 + 0.44*4651.16 = 22046.5

The mean of the number of people ordering the program is 22,046.5 and the standard deviation is 4,651.16.

6 0
3 years ago
Help<br> plzrtyujngfrthtrf<br> g<br> pls
Stella [2.4K]

Answer:

4\frac{1}{4}

7 0
3 years ago
Read 2 more answers
the perimeter of a rectangle of a rectangular field is 76 ft. The length is 12 ft longer than the width. Find the fields dimensi
timurjin [86]
It’ll be length= 12ft width= 26ft
(76-24)/2= width
8 0
3 years ago
a box of marbles can be shared equally among 6,7,or 8 students with 4 marbles left over each time.what is the least possible num
Vlad1618 [11]
If there are 4 marbles left over each time, then we can forget about them for now.

So the question is, what is the smallest number than can be divided into 6,7 and 8?

the numbers have only one non-1 divisor in common: both 6 and 8 are divisible by 3.

so for our purposes we can "delete" one 2 and ask:


what is the smallest number than can be divided into 3,7 and 8 ?

There are no more divisors in common, so we just have to multiply them: 3*7*8=21*8=168


and the 4 marbles "extra"? We add them to this sum.


the the smallest possible number in the box is 168+4=172.
3 0
3 years ago
Other questions:
  • A square wall tile has an area of 58,800 square millimeters.between which two measurements is the length of one side
    6·1 answer
  • REALLY EASY NEED ANSWER BY 10:00 P. M. AND WILL GIVE BRAINLEIST. PLS HURRY IF YOU HAVE TIME PLEASE ANSWER OTHER QUESTIONS PLS TH
    15·1 answer
  • What's the area in square meters of a rectangle with the length of 2.1 m and a height of point 8 m
    14·1 answer
  • Two angles of a triangle are 40 degrees and 62 degrees ; what is the third angle’s measure ?
    13·2 answers
  • In the diagram, point o is the center of the circle
    5·1 answer
  • Aaron gets paid $7.00 an hour at his job.how much money would he earn if he spends 2 hours a day working
    7·2 answers
  • For a magic trick , Ashley has a classmate pick one card from a standard deck of cards . what is the probability of Ashley 's cl
    15·2 answers
  • 3x-3y=-6 -5x+6y=12 elimination using multiplication
    7·1 answer
  • I need to find the value of each variable in the following parallelograms
    9·1 answer
  • Are the two triangles congruent?
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!