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yulyashka [42]
4 years ago
10

I need help with number 3 .

Mathematics
1 answer:
djverab [1.8K]4 years ago
5 0

Answer:

there are 6 activities therefore 360/6 = 60 minutes on each activity

Step-by-step explanation:

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Is the following shape a rectangle?how do you know?​
adelina 88 [10]

Answer:

The following shape is not a rectangle, but a square. I know this because the length and width are the same amount of square inch(feet, what ever the square counts for on your graph.) and rectangles width are typically longer than their length. However a square shares the same length and width,  

Step-by-step explanation:

8 0
4 years ago
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Answers;<br> A) 135 degree’s<br> B) 30 Degree’s<br> C) 180 or 0 Degree’s<br> D) 90 Degree’s
Vladimir [108]

Answer:

C). 0 degrees

Step-by-step explanation:

The given equation is:

-4 + 6 sinx = -4 + 4 sinx

adding 4 on both sides:

4 - 4 + 6 sinx = 4 - 4 + 4 sinx

6sinx = 4sinx

dividing by 2 on both sides, we get:

6sinx/2 = 4sinx/2

3 sinx = 2 sinx

subtracting 2 sinx from both sides we get:

sin x = 0

x = sin⁻¹ (0)

x = 0 degrees

4 0
3 years ago
3(-x - 4) = 3x + 5(x + 2)
Ket [755]
3(-x - 4) = 3x + 5(x + 2)
x=-2
7 0
3 years ago
Read 2 more answers
What is the first and second derivative of xe^(2x)?
Nimfa-mama [501]
f(x)=xe^{2x}\\\\f'(x)=x'e^{2x}+x(e^{2x})'=e^{2x}+xe^{2x}\cdot2=2xe^{2x}+e^{2x}=e^{2x}(2x+1)\\\\f''(x)=(e^{2x})'(2x+1)+e^{2x}(2x+1)'=e^{2x}\cdot2(2x+1)+e^{2x}\cdot2\\\\=e^{2x}(4x+2)+2e^{2x}=(4x+2+2)e^{2x}=(4x+4)e^{2x}\\\\Answer:\\\boxed{f'(x)=(2x+1)e^{2x}\ and\ f''(x)=(4x+4)e^{2x}}
5 0
3 years ago
Read 2 more answers
PLZZZ HELP NOOOOWWW!!!
maw [93]
Hello!

You can use the Pythagorean Theorem

a^{2} + b^{2} = c^{2}

C is the hypotenuse which is the line across the diameter
a and b are the other sides

You have to find the bottom side of the triangle

9 - 6 = 3

Put in the values you know

9^{2} + 3^{2} = c^{2}

Square the numbers

81 + 9 =  c^{2}

Add

90 =  c^{2}

take the square root of both sides

\sqrt{90} = c

The answer is C)  \sqrt{90}

Hope this helps!
4 0
3 years ago
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