Answer:
Step-by-step explanation:
![7- \sqrt[3]{2-x} =12](https://tex.z-dn.net/?f=7-%20%5Csqrt%5B3%5D%7B2-x%7D%20%3D12)
we have to just keep in mind to do the same operation to both sides of the equal sign
![7-7- \sqrt[3]{2-x} =12-7](https://tex.z-dn.net/?f=7-7-%20%5Csqrt%5B3%5D%7B2-x%7D%20%3D12-7)
; subtract 7 from both sides
![- \sqrt[3]{2-x} = 5](https://tex.z-dn.net/?f=-%20%5Csqrt%5B3%5D%7B2-x%7D%20%3D%205)
; multiply both sides by -1
![\sqrt[3]{2-x} = -5](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2-x%7D%20%3D%20-5)
; raise both sides to the power 3
2-x = (-5)³
2-x = -125 ; subtract 2 from both sides
-x = -125-2
-x =-127; multiply both sides by -1
x= 127
I think 10 is the answer, correct me
Step-by-step explanation:
A function f(x) can be scaled by a factor of "a" and translated by (h,k) by the relation:
f(x) -> a f(x-h)+k
substitute f(x) by sqrt(x), then
sqrt(x) -> a*sqrt(x-h) + k
So the given equation is derived from f(x) = sqrt(x), hence a radical function.
Answer:
and the addition will be p+q
Step-by-step explanation:
the diffrence between p and q is u have to add so the answer will be p-q
Pretty sure it is nine. I hope I helped
