Answer:
7.8 units
Step-by-step explanation:
P(Xp, Yp)= (7,7)
Q(Xq, Yq)= (1,2)
distance= l=
l=
l= 
l=
l=7.8102 (to 4 dec. places)
I= 7.8 (to nearest tenth)
Answer:
(a+b)(a-b)
Step-by-step explanation:
because (a+b)(a-b):
If you use FOIL it will work backwards
Answer: option A) 1/3
Justification:
1) The probability that a point chosen at random <span>in the regular hexagon lies in the shaded region is equal to:
area of the shaded region
---------------------------------------
area of the hexagon
2) The hexagon is formed by 6 equal triangles and the shaded area is formed by 2 of those triangles.
3) Therefor,naming x the area of one triangle, the the above fraction is equal to:
area of two triangles 2x
------------------------------- = -------- = 2/6 = 1/3
area of six triangles 6x
And that is the answer: 1/3
</span>
Answer:

Step-by-step explanation:
<u>Given Data:</u>
Base area =
= 108 in.²
Volume = V = 729 in.³
<u>Required:</u>
Height = h = ?
<u>Formula:</u>

<u>Solution:</u>
For h, rearranging formula:
![\displaystyle h = \frac{V}{A_{B}} \\\\h =\frac{729 \ in.^3}{108 \ in.^2} \\\\h = 6.75 \ in.\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20h%20%3D%20%5Cfrac%7BV%7D%7BA_%7BB%7D%7D%20%5C%5C%5C%5Ch%20%3D%5Cfrac%7B729%20%5C%20in.%5E3%7D%7B108%20%5C%20in.%5E2%7D%20%5C%5C%5C%5Ch%20%3D%206.75%20%5C%20in.%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)