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3 years ago

Which arc must be a major arc?

Mathematics

1 answer:

frosja888 [35]3 years ago

8 0

A major arc is an arc that is larger than a semicircle. The only arc that is larger than a semicircle in the answer choices is D. NRC.

I hope this helps :)

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Hal, Zelda, Maya, and Jason each recorded the height and age of five classmates. They used the data to create the tables below.

Mariana [72]

A table (relation) may or may not represent a function

The table that represents a function is Hal's table

<h3><u>Tables and relations</u></h3>

For a table to represent a function, then the input values must point to exactly one output value.

This means that:

Each height entry must correspond to exactly one age entry

From the given tables (see attachment), we can conclude that

Hal's table represents a function

This is so because, the age entries on this table has one corresponding one height entry

Read more about relations and functions at:

brainly.com/question/2253924

7 0

2 years ago

(Please help me with this one it is due in ten minutes :'(

Flura [38]

Answer:

I think the answer is C

Step-by-step explanation:

First you need to find 2 coordinates on the graph. (2,3) (4,6)

Use the formula M= y2-y1 ÷ x2-x1

Then m= 6-3 ÷ 4-2

Then m= 3÷2 = 1.5

So the slope should be 1.5 or 1 1/2

6 0

3 years ago

Suppose heights of seasonal pine saplings are normally distributed and have a known population standard deviation of 17 millimet

Mumz [18]

Answer:

$296.693\leq x\leq 319.307$

Step-by-step explanation:

The confidence interval for the population mean x can be calculated as:

$x'-z_{\alpha /2}\frac{s}{\sqrt{n} } \leq x\leq x'+z_{\alpha /2}\frac{s}{\sqrt{n} }$

Where x' is the sample mean, s is the population standard deviation, n is the sample size and $z_{\alpha /2}$ is the z-score that let a proportion of $\alpha /2$ on the right tail.

$\alpha$ is calculated as: 100%-99%=1%

So, $z_{\alpha/2}=z_{0.005}=2.576$

Finally, replacing the values of x' by 308, s by 17, n by 15 and $z_{\alpha /2}$ by 2.576, we get that the confidence interval is:

$308-2.576\frac{17}{\sqrt{15} } \leq x\leq 308+2.576\frac{17}{\sqrt{15} }\\308-11.307 \leq x\leq 308+11.307\\296.693\leq x\leq 319.307$

6 0

3 years ago

A hospital employees a total of 77 nurses and doctors the ratio of nurses to doctors is 92 how many nurses are employed at the h

IgorLugansk [536]

I think if I done it right 15 I hope it helps

4 0

3 years ago

Kyle is pulled back on a swing so that the rope forms an angle of 30° with the vertical. The distance from the top of the swing

olga_2 [115]

This would be 12 - 12*cos(30) = 12 - 6 $\sqrt{3}$ = 1.608 ft off the ground.

6 0

3 years ago