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vagabundo [1.1K]
3 years ago
9

" class="latex-formula"> = -1
find the value of x
Mathematics
2 answers:
ValentinkaMS [17]3 years ago
5 0

Answer:

x=-4

Step-by-step explanation:

-1x4=-4

i hope this helps

AlekseyPX3 years ago
3 0
I’m pretty sure the answer is -4 I hope this helps
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natka813 [3]

Answer:

i dont know if this is right but i think that would be the second one

Step-by-step explanation:

i dont know if this is right but i think that would be the second one

3 0
3 years ago
PLS PLS HELP, I DONT WANT TO FAIL!!
Flura [38]

Answer:

2.0 seconds

Step-by-step explanation:

<u>Given quadratic functions</u>:

\begin{cases}y=-7x^2+26x+3\\y=-6x^2 +23x+5\end{cases}

To find the time, in seconds, that the balloons collided at the highest point, <u>substitute</u> one equation into the other equation and rearrange to <u>equal zero</u>:

\begin{aligned}-6x^2+23x+5 & = -7x^2+26x+3\\-6x^2+23x+5+7x^2 & = -7x^2+26x+3+7x^2\\x^2+23x+5 & = 26x+3\\x^2+23x+5-26x & = 26x+3-26x\\x^2-3x+5& = 3\\x^2-3x+5-3& = 3-3\\x^2-3x+2& = 0\end{aligned}

<u>Factor</u> the quadratic:

\begin{aligned}x^2-3x+2 & = 0\\x^2-2x-x+2 & = 0\\x(x-2)-1(x-2) & = 0\\(x-1)(x-2) & = 0\\\end{aligned}

Apply the <u>zero-product property</u> to solve for x:

\implies (x-1)=0 \implies x=1

\implies (x-2)=0 \implies x=2

Therefore, the balloons collided at 1 second and 2 seconds.  

To find at which time the highest point of collision occured, substitute both values of x into one of the functions:

f(1)=-6(1)^2 +23(1)+5=22

f(2)=-6(2)^2 +23(2)+5=27

Therefore, the time, in seconds, that the balloons collided at the highest point is 2.0 seconds.

Learn more about quadratic systems of equations here:

brainly.com/question/27930827

8 0
1 year ago
Read 2 more answers
How do I answer this
solniwko [45]

Answer:

can you put another screen shot its blurry on my end.

Step-by-step explanation:

4 0
3 years ago
CosA+cosB+cosC+cos(A+B+C)= cos(A+B).cos(B+C).cos(C+A)
RoseWind [281]

Answer:

cos (A+B+C)

Step-by-step explanation:

as A,B,C, are triangle we have A,B and C as 180

cost

8 0
3 years ago
Figure EFGHK as shown below is to be transformed to figure E′F′G′H′K′ using the rule
MAVERICK [17]

9514 1404 393

Answer:

  (a)  (4, 8)

Step-by-step explanation:

Apply the transformation rule to the coordinates of point H.

  (x, y) → (x +8, y +5)

  H(-4, 3) → H'(-4 +8, 3 +5) = H'(4, 8)

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3 years ago
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