<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B4%7D" id="TexFormula1" title="\frac{x}{4}" alt="\frac{x}{4}" align="absmiddle

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vagabundo [1.1K]

3 years ago

" class="latex-formula"> = -1
find the value of x

Mathematics

2 answers:

ValentinkaMS [17]3 years ago

5 0

Answer:

x=-4

Step-by-step explanation:

-1x4=-4

i hope this helps

AlekseyPX3 years ago

3 0

I’m pretty sure the answer is -4 I hope this helps

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Which of the following is equivalent to the radical expression below? 5^8*13

Bezzdna [24]

Answer:

$(d)$ $5^{8.13} = 5^{8} * 5^{\frac{1}{10}} * 5^{\frac{3}{100}}$

Step-by-step explanation:

Given

$5^{8.13}$

Required

Select an equivalent expression

$5^{8.13}$

Simplify the power

$5^{8.13} = 5^{8 + 0.1 + 0.03}$

Apply law of indices:

$5^{8.13} = 5^{8} * 5^{0.1} * 5^{0.03}$

Express decimal as fractions

$5^{8.13} = 5^{8} * 5^{\frac{1}{10}} * 5^{\frac{3}{100}}$

5 0

3 years ago

Solve each inequality, and then drag the correct solution graph to the inequality.

Nesterboy [21]

The correct solution graph to the inequalities are

$4(9x-18)>3(8x+12)$ → C

$-\frac{1}{3}(12x+6) \geq -2x +14$ → A

$1.6(x+8)\geq 38.4$ → B

(NOTE: The graphs are labelled A, B and C from left to right)

For the first inequality,

$4(9x-18)>3(8x+12)$

First, clear the brackets,

$36x-72>24x+36$

Then, collect like terms

$36x-24x>36+72\\12x >108$

Now divide both sides by 12

$\frac{12x}{12} > \frac{108}{12}$

∴ $x > 9$

For the second inequality

$-\frac{1}{3}(12x+6) \geq -2x +14$

First, clear the fraction by multiplying both sides by 3

$3 \times[-\frac{1}{3}(12x+6)] \geq3 \times( -2x +14)$

$-1(12x+6) \geq -6x +42$

Now, open the bracket

$-12x-6 \geq -6x +42$

Collect like terms

$-6 -42\geq -6x +12x$

$-48\geq 6x$

Divide both sides by 6

$\frac{-48}{6} \geq \frac{6x}{6}$

$-8\geq x$

∴ $x\leq -8$

For the third inequality,

$1.6(x+8)\geq 38.4$

First, clear the brackets

$1.6x + 12.8\geq 38.4$

Collect likes terms

$1.6x \geq 38.4-12.8$

$1.6x \geq 25.6$

Divide both sides by 1.6

$\frac{1.6x}{1.6}\geq \frac{25.6}{1.6}$

∴ $x \geq 16$

Let the graphs be A, B and C from left to right

The first graph (A) shows $x\leq -8$ and this matches the 2nd inequality

The second graph (B) shows $x \geq 16$ and this matches the 3rd inequality

The third graph (C) shows $x > 9$ and this matches the 1st inequality

Hence, the correct solution graph to the inequalities are

$4(9x-18)>3(8x+12)$ → C

$-\frac{1}{3}(12x+6) \geq -2x +14$ → A

$1.6(x+8)\geq 38.4$ → B

Learn more here: brainly.com/question/17448505

8 0

2 years ago

Plssssss help meh with this

Naddik [55]

Answer:

<h2><em><u>ᎪꪀsωꫀᏒ</u></em></h2>

➪-263

Step-by-step explanation:

-3x²-20

-3(-9)²-20

-3(81)-20

-243-20

-263

5 0

2 years ago

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The price of an item has risen to $301 today. Yesterday it was $140 Find the percentage increase.

Ludmilka [50]

Answer: 115%

Step-by-step explanation: ur welcome

7 0

3 years ago

Read 2 more answers

A.B,and C are collinear. AB=5x-19,and BC= 3x+4. Find an expression for AC if B is between A and C.

uysha [10]

Find A <span>if B is between A and C.
</span><span>A.B,and C are collinear so A, B and C are line up in a line</span>

AC = AB + BC

AB=5x-19,and BC= 3x+4 given;

AC = 5x-19 + 3x+4

Simplify

AC = 8x -15

4 0

3 years ago