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3 years ago

-2(x+6)+6x how to simplify

Mathematics

2 answers:

Nesterboy [21]3 years ago

7 0

Answer:

4x + -12

Step-by-step explanation:

First you need to multiply the -2 by the x and 6. This would simplify it to -2x + -12.

Then you need to add the 6x to the -2x.

This will bring the simplified answer to 4x + -12

GuDViN [60]3 years ago

5 0

Answer:

4x - 12

Step-by-step explanation:

1. Distribute the -2(Do -2 times x and -2 times 6)

-2x - 12 + 6x

2. Combine like terms

4x - 12.

That is it.

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umka21 [38]

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3 years ago

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The quotient of 24 and the sum of<br> -4 and<br> -8

pychu [463]

Answer:

0.75

Step-by-step explanation:

-4 x -8 = 32

24 divided by 32 = 0.75

6 0

3 years ago

Find the height of the triangle.

Ierofanga [76]

Answer:

The value of x = 3.42

Step-by-step explanation:

Formula:

Sin ∅ = Opposite side /Hypotenuse

From the figure we can see a right angled triangle.

One angle is given, hypotenuse = 10 and height = x.

To find the value of x

sin 20 = Opposite side/hypotenuse = x/10

x = 10 * sin 20

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Therefore the value of x = 3.42

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3 years ago

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The equation t^3=a^2 shows the relationship between a planet’s orbital period, T, and the planet’s mean distance from the sun, A

ankoles [38]

Answer:

2√2

Step-by-step explanation:

We can find the relationship of interest by solving the given equation for A, the mean distance.

<h3>Solve for A</h3>

$T^3=A^2\\\\A=\sqrt{T^3}=T\sqrt{T}\qquad\text{take the square root}$

<h3>Substitute values</h3>

The mean distance of planet X is found in terms of its period to be ...

$D_x=T_x\sqrt{T_x}$

The mean distance of planet Y can be found using the given relation ...

$T_y=2T_x\\\\D_y=T_y\sqrt{T_y}=2T_x\sqrt{2T_x}=(2\sqrt{2})T_x\sqrt{T_x}\\\\D_y=2\sqrt{2}\cdot D_x$

The mean distance of planet Y is increased from that of planet X by the factor ...

2√2

8 0

2 years ago

Triangle ABC has vertices at A(-2,1), B(-2,-3), and C(1,-2). What is the area of the triangle? a 18 square units b 9 square unit

natka813 [3]

Answer:

Option C. 6 square units

Step-by-step explanation:

we know that

Heron's Formula is a method for calculating the area of a triangle when you know the lengths of all three sides.

Let

a,b,c be the lengths of the sides of a triangle.

The area is given by:

$A=\sqrt{p(p-a)(p-b)(p-c)}$

where

p is half the perimeter

p= $\frac{a+b+c}{2}$

we have

Triangle ABC has vertices at A(-2,1), B(-2,-3), and C(1,-2)

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance AB

$d=\sqrt{(-3-1)^{2}+(-2+2)^{2}}$

$d=\sqrt{(-4)^{2}+(0)^{2}}$

$dAB=4\ units$

step 2

Find the distance BC

$d=\sqrt{(-2+3)^{2}+(1+2)^{2}}$

$d=\sqrt{(1)^{2}+(3)^{2}}$

$dBC=\sqrt{10}\ units$

step 3

Find the distance AC

$d=\sqrt{(-2-1)^{2}+(1+2)^{2}}$

$d=\sqrt{(-3)^{2}+(3)^{2}}$

$dBC=\sqrt{18}\ units$

step 4

$a=AB=4\ units$

$b=BC=\sqrt{10}\ units$

$c=AC=\sqrt{18}\ units$

Find the half perimeter p

p= $\frac{4+\sqrt{10}+\sqrt{18}}{2}=5.70\ units$

Find the area

$A=\sqrt{5.7(5.7-4)(5.7-3.16)(5.7-4.24)}$

$A=\sqrt{5.7(1.7)(2.54)(1.46)}$

$A=\sqrt{35.93}$

$A=6\ units^{2}$

7 0

3 years ago