Solve –3x^2 – 4x – 4 = 0

2 answers:

8 0

3x^2 – 4x – 4 = 0



multiply the first coefficient by the last coefficient: 

3 x -4= -12 

Now think, what adds to the 2nd coefficient (-4) and multiplies to -12? 

-6 and 2 

rewrite your equation: 

3x^2 - 6x + 2x - 4 <==== this is essentially the same equation 

now split it... 

3x^2 - 6x 

AND 

2x -4 

factor each one so that both share a common factor: 

3x(x-2) 

AND 

2(x-2) 

Now combine them: 

(3x+2)(x-2)

raketka [301]3 years ago

4 0

-3x^2-6x+2x-4 =-3x (x-2)+2 (x-2) =(-3x+2)(x-2) -3x+2=0 X=2/3 X-2=0 X=2 Hope it helps! !!!!

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Write the equation of a line Parallel to the given line and passes through points (-4, -3); (2, 3). Hints find the slope by usin

julia-pushkina [17]

First, we obtain the gradient (slope) of the first parallel line

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Recall that since both lines are parallel, we have that,

$m_1=m_2$

Thus

$m_2\text{ = 1}$

Hence, we can find the equation of the parallel line given that it passes through the points (-4, -3)

Using

$\begin{gathered} y\text{ = mx + c} \\ \text{where m = m}_2\text{ = 1} \\ \text{and x = -4 , y = -3, we have} \\ -3\text{ = 1(-4) + c} \\ -3\text{ = -4 + c} \\ 4\text{ - 3 = c} \\ c\text{ = 1} \\ \text{Thus, the equation of the line is y = (1)x + 1} \\ y\text{ = x + 1} \end{gathered}$

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1 year ago

What’s the correct answer for this question?

weqwewe [10]

Answer:

Last answer choice

Step-by-step explanation:

The AAS congruence theorem uses two adjacent angles, followed by a side length on the side (not in between the angles.) Therefore, the first answer is ruled out (because it deals with angles and not sides), and the second answer is ruled out because it involves side lengths between angles. LP=MO may be true, but it does not compare the two triangles that we are interested in. However, the last answer choice is correct, because a midpoint divides a line exactly in half, meaning that both halves are the same length and therefore congruent. Therefore, the last answer choice is correct. Hope this helps!

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8_murik_8 [283]

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$x=\frac{-4+\sqrt{4^2-4*2*(-15)}}{2*2},\frac{-4-\sqrt{4^2-4*2*(-15)}}{2*2}\\ \\ x=\frac{-4+\sqrt{16-(-120)}}{4},\frac{-4-\sqrt{16-(-120)}}{4}\\ \\ x=\frac{-4+\sqrt{136}}{4},\frac{-4-\sqrt{136}}{4}\\ \\ x=1.92,-3.92$

In short, your x-intercepts (rounded to the hundredths) are (1.92,0) and (-3.92,0).

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