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tensa zangetsu [6.8K]
3 years ago
12

Solve –3x^2 – 4x – 4 = 0

Mathematics
2 answers:
vredina [299]3 years ago
8 0
<span> 3x^2 – 4x – 4 = 0

</span>

<span>multiply the first coefficient by the last coefficient: </span>

<span>3 x -4= -12 </span>

<span>Now think, what adds to the 2nd coefficient (-4) and multiplies to -12? </span>

<span>-6 and 2 </span>

<span>rewrite your equation: </span>

<span>3x^2 - 6x + 2x - 4 <==== this is essentially the same equation </span>


<span>now split it... </span>

<span>3x^2 - 6x </span>

<span>AND </span>

<span>2x -4 </span>

<span>factor each one so that both share a common factor: </span>

<span>3x(x-2) </span>

<span>AND </span>

<span>2(x-2) </span>

<span>Now combine them: </span>

<span>(3x+2)(x-2) </span>

raketka [301]3 years ago
4 0
-3x^2-6x+2x-4 =-3x (x-2)+2 (x-2) =(-3x+2)(x-2) -3x+2=0 X=2/3 X-2=0 X=2 Hope it helps! !!!!
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Evgesh-ka [11]

Answer:

x=-3/7 and y=_23/7

Step-by-step explanation:

y=-4x-5 and y=3x-2

using comparison method

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substituting the value of x

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3+7(0.7+1.3)<br> What is the answer and how to solve it?
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When you see this kind of question use « BODMAS »
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3+7(0.7+1.3)
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2 years ago
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leva [86]

Answer:

radical 65

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4+7 are squred and under a radical bar

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