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2 years ago

The diameter of a circle is 7 cm. Find its area to the nearest tenth.

Mathematics

2 answers:

lesya692 [45]2 years ago

4 0

The answer is 38.5 i hope this helps

NARA [144]2 years ago

3 0

Answer:

38.5 cm

Step-by-step explanation:

1. To find the radius divide 7 by 2 which is 3.5

2. Then multiply 3.5 by itself which is 12.25

3. Next multiply 12.25 by 3.14 ( 3.14 = $\pi$ = pi )

4. Lastly your answer will be 38.5

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Taylor and Jesse are buying a magazine for $3.75 and a snack for $2.49 what is s the total cost of the two items?

Kazeer [188]

Hey There!

The answer you are looking for is; $6.24!

Work:

You simply add $3.75 + $2.49 together.

Since .75 + .29 = 1.24, you carry the one over to the full dollar.

3 + 2 + 1 = 6.

= 6.24

Hope I helped! 5 stars and brainliest are always appreciated.

7 0

3 years ago

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In a cirde, what does the ratio A/^2 represent?

inna [77]

Answer:

D.pi

Step-by-step explanation:

Because it’s pi

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2 years ago

Find the value of c that makes each trinomial a perfect square.<br> x^2-13x+c

vova2212 [387]

Answer:

169/4

Step-by-step explanation:

x² - 13x + c

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(13/2)² = 169/4 or 42 ¼

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2 years ago

A rectangular garden has a length that is modeled by the expression 2 x – 7 and a width of 3 x 2 + 4 x. Part A: What is the area

borishaifa [10]

Area: (2x - 7) * (3*2 + 4x)
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5 0

3 years ago

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You are graphing Square ABCDABCDA, B, C, D in the coordinate plane. The following are three of the vertices of the square: A(4,

Kitty [74]

Answer:

D(4,-3)

Step-by-step explanation:

Given three of the vertices of the square: A(4, -7), B(8, -7),C(8, -3)

Let the coordinate of the fourth vertex be D(x,y).

We know that diagonals of a square are perpendicular bisector. So, the midpoint of both diagonals is the same.

The diagonals are BD and AC

Midpoint of BD = Midpoint of AC

$\left(\dfrac{8+x}{2},\dfrac{-7+y}{2}\right) =\left(\dfrac{4+8}{2},\dfrac{-7+(-3)}{2}\right)\\ \left(\dfrac{8+x}{2},\dfrac{y-7}{2}\right) =\left(\dfrac{12}{2},\dfrac{-10}{2}\right)\\ \left(\dfrac{8+x}{2},\dfrac{y-7}{2}\right) =\left(6,-5\right)\\$Therefore$:\\\dfrac{8+x}{2}=6\\8+x=12\\x=12-8\\x=4\\$Similarly$\\\dfrac{y-7}{2}=-5\\y-7=-5*2\\y-7=-10\\y=-10+7=-3$

The coordinates of the fourth vertex is D(4,-3)

3 0

3 years ago