It would be the answer with Juana. Additive integers are adding a postive and negative number to add to zero ex) -5+5=0. So in this situation you can think of west and east as positive and negative.
First, write out the statement as an inequality so that it looks like this: x<span>≤11/5
Then you graph it on a number line, and since you know anything greater/less than or equal to is a closed circle since it includes the value 11/5, you would plot a closed circle on 11/5 on a number line and draw and arrow pointing towards the left to show that only values 11/5 or under can satisfy x.
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Answer:
The answer to your proble I'm slow intercept from is y=-2x+8
Step-by-step explanation:
Answer:
- vertical asymptote: x = 7
- slant asymptote: y = x+9
Step-by-step explanation:
The vertical asymptotes are found where a denominator factor is zero (and there is no corresponding numerator factor to cancel it). Here, that is at x = 7.
There is no horizontal asymptote because the numerator is of higher degree than the denominator.
When you divide the numerator by the denominator, you get ...
y = (x +9) +60/(x -7)
Then when x gets large, the behavior is governed by the terms not having a denominator: y = x +9. This is the equation of the slant asymptote.
The slope of the line is -4