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Sladkaya [172]
3 years ago
13

If a gradient of line a is 4 what is the gradient of the line perpendicular to a

Mathematics
1 answer:
katovenus [111]3 years ago
5 0
\bf \textit{perpendicular, negative-reciprocal slope for}\quad 4\implies \cfrac{4}{1}\\\\
negative\implies  -\cfrac{4}{ 1}\qquad reciprocal\implies - \cfrac{ 1}{4}
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Please answer and explain the link below
Leviafan [203]

Answer:

See explanation.

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Functions
  • Function Notation

<u>Calculus</u>

Limits

  • Right-Side Limit:                                                                                             \displaystyle  \lim_{x \to c^+} f(x)
  • Left-Side Limit:                                                                                               \displaystyle  \lim_{x \to c^-} f(x)

Limit Rule [Variable Direct Substitution]:                                                             \displaystyle \lim_{x \to c} x = c

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle f(x) = \left \{ {{\sqrt{x + 1}, \ x < 3} \atop {5 - x, \ x \geq 3}} \right.

<u>Step 2: Find Right Limit</u>

  1. Substitute in variables [Right-Side Limit]:                                                      \displaystyle  \lim_{x \to 3^+} 5 - x
  2. Evaluate limit [Limit Rule - Variable Direct Substitution]:                           \displaystyle  \lim_{x \to 3^+} 5 - x = 5 - 3
  3. Subtract:                                                                                                         \displaystyle  \lim_{x \to 3^+} 5 - x = 2

∴ the right-side limit equals 2.

<u>Step 3: Find Left Limit</u>

  1. Substitute in variables [Left-Side Limit]:                                                       \displaystyle  \lim_{x \to 3^-} \sqrt{x + 1}
  2. Evaluate limit [Limit Rule - Variable Direct Substitution]:                           \displaystyle  \lim_{x \to 3^-} \sqrt{x + 1} = \sqrt{3 + 1}
  3. [√Radical] Add:                                                                                             \displaystyle  \lim_{x \to 3^-} \sqrt{x + 1} = \sqrt{4}
  4. [√Radical] Evaluate:                                                                                       \displaystyle  \lim_{x \to 3^-} \sqrt{x + 1} = 2

∴ the left-side limit equals 2.

<u>Step 4: Find Limit</u>

<em>The right and left-side limits are equal.</em>

∴  \displaystyle  \lim_{x \to 3} f(x) = 2

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

Book: College Calculus 10e

4 0
3 years ago
Create a linear equation in slope intercept form that contains the points (1,4) and (4,7).​
S_A_V [24]

Answer:

y = x + 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (1, 4) and (x₂, y₂ ) = (4, 7)

m = \frac{7-4}{4-1} = \frac{3}{3} = 1, hence

y = x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation.

Using (1, 4), then

4 = 1 + c ⇒ c = 4 - 1 = 3

y = x + 3 ← equation in slope- intercept form

4 0
4 years ago
You buy 3 pairs of pants at an original cost of $24.99 and the sale is buy 1 get the 2nd pair half off. The sales tax is 6%. How
Finger [1]

Answer:

  D.  $66.23

Step-by-step explanation:

The sale discounts your purchase by half the price of a pair of pants, so you pay for 2.5 pairs of pants. The sale price of the pants is then ...

  $24.99 × 2.5 = $62.48

The added tax multiplies this value by 1.06, so you pay ...

  1.06 × $62.48 = $66.23

_____

<em>Comment on the answer</em>

Whether you pay $66.23 or $66.22 depends on how the discount is calculated. If you get the benefit of the half-penny (the discount is rounded up), then the sale price is $62.47 and the total is $66.22.

4 0
3 years ago
What are the zeros of the fuction f(x)=x2-13x-30
uysha [10]
X²-13x-30=0
(x-15)(x+2)=0
x = -2 or 15
3 0
3 years ago
Driven any two two number witch is greater the lcm of the number or gcf of the the number?why?
avanturin [10]
Lcm because a multiple is always greater then a factor.
4 0
3 years ago
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