The correct answer is 11.3
A bearing of 34° corresponds to corresponding angle of θ=90-34=56°
The (x,y) values for the position of the ship after completing its first heading are:
x=(10.4cos 56)
y=(10.4sin56)
The trigonometric angle for θ=90-90=0
The (x,y) values for the postion of the ship after completing the second bearing is:
x=(10.4 cos56)+(4.6cos0)≈10.4 mi
y=(10.4sin56)+(4.6sin0)≈8.6mi
the distance from the port will therefore be:
d=√(10.4²+8.6²)≈13.5 miles
It trigonometric angles is:
θ=arctan(y/x)
θ=arctan(8.6/10.4)
θ≈39.6°
Thus the bearing angle is:
90-39.6=50.4°
Let r, g and b represent red, green and blue.
r+g+b = 74
r=g-1
b=r+g
Again, r+g+b = 74. Let's substitutte r+g for b: r+g+(r+g) = 74.
Next, let's eliminate r. Use r=g-1. Then g-1 + g + g-1 + g = 74
Combining the g terms, 4g - 2 = 74 => 4g = 76 => g = 19
Recall that r=g-1
and
b=r+g
Find r. If r=g-1, and g=19, then r = 19-1=18
Find b: b = r+g = 18+19=37
So there are 37 blue candies, 18 red candies and 19 green candies.
Check: 37+18+19=74 ??? Yes.
The unknown number would be 11
738 + 164 = 902
902 / 82 = 11
Ans: 11
Answer:6/8
Step-by-step explanation:
