Answer:
The surface area of the pyramid is 466,137 squared cubits
Step-by-step explanation:
This is simply asking us to find the surface area of the square based pyramid with the given dimensions.
The first thing we need to know is the principle for finding the surface area of such pyramidal shapes. To get the surface area of a pyramid, we will have to add the base area to the area of the side faces ( lateral area)
The base area of the square based pyramid, will be the same as the area of a square which is = 453 cubits X 453 cubits =
The lateral area has already been given to us as 260,928 squared cubits.
The surface area of the pyramid is 260,928 + 205209 = 466137 squared cubits
Hence, the surface area of the pyramid is 466137 squared cubits
M= 20 because the rate of change is -3.
This is the concept of density, volume and mass of different materials; To calculate for the volume of an aluminium material with density of 2.375 grams per cubic centimeter and a mass of 0.78 Kilogram we proceed as follows;
Density=mass/volumemaking volume the subject we get;volume=mass/densitythus;mass=0.78 kg= 780 gdensity=2.375 g/cm^3Hence,volume=780/2.375=328.421 cm^3
Hi!
Our goal is to isolate x on one side by doing the same operation on both sides.
First let's use the distribution property.
-2 x 6 = -12
-2 x 3 = -6
-12x - 6 = -27 - 5x
Add 6 to both sides
-12x - 6 + 6 = -27 + 6 - 5x
-12x = -21 - 5x
Add 5x to both sides
-12x + 5x = -21 - 5x + 5x
-7x = -21
Divide by -7 on both sides
-7x/-7 = -21/-7
x = 3
The answer is x = 3
Hope this helps! :)
-2; 3-5= -2 or -5 - (-3)
-1; 4-5 or -5 - (-4) = -1
-5; -6 - (-1)= 1-6= -5
