How do you prove that a point on a perpendicular bisector is equidistant from the endpoints of the segment it intersects?
1 answer:
Check the picture drawn
Consider the line segment AB,
let M be the midpoint of AB, so AM=MA
erect the perpendicular MT to AB from point M. Pick a point P on MT and join it to the points A and B
The triangles PMA and PMB are congruent from the Side Angle Side congruence postulate:
AM=MA, PM is common and m(PMA)=m(PMB)=90°, as MT is perpendicular to AB
so PA=PB
Consider the line segment AB,
let M be the midpoint of AB, so AM=MA
erect the perpendicular MT to AB from point M. Pick a point P on MT and join it to the points A and B
The triangles PMA and PMB are congruent from the Side Angle Side congruence postulate:
AM=MA, PM is common and m(PMA)=m(PMB)=90°, as MT is perpendicular to AB
so PA=PB
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Answer:
Average weight of the bags of potatoes is 3.8 pounds.
Step-by-step explanation:
Given:
Weight of the first bag, pounds.
Weight of the second bag is 0.4 pounds less than twice the weight of first bag. This means,
Weight of the third bag is 0.6 pounds more than that of the first bag. This means,
Weight of the fourth bag is 0.3 pounds less than that of the second bag. This means,
Therefore, the average weight of the bags of potatoes is given as the sum of all the weights and then divide the sum by 4. Therefore,
Therefore, average weight of the bags of potatoes is 3.8 pounds.