How do you prove that a point on a perpendicular bisector is equidistant from the endpoints of the segment it intersects?
1 answer:
Check the picture drawn
Consider the line segment AB,
let M be the midpoint of AB, so AM=MA
erect the perpendicular MT to AB from point M. Pick a point P on MT and join it to the points A and B
The triangles PMA and PMB are congruent from the Side Angle Side congruence postulate:
AM=MA, PM is common and m(PMA)=m(PMB)=90°, as MT is perpendicular to AB
so PA=PB
Consider the line segment AB,
let M be the midpoint of AB, so AM=MA
erect the perpendicular MT to AB from point M. Pick a point P on MT and join it to the points A and B
The triangles PMA and PMB are congruent from the Side Angle Side congruence postulate:
AM=MA, PM is common and m(PMA)=m(PMB)=90°, as MT is perpendicular to AB
so PA=PB
You might be interested in
Answer:
Step-by-step explanation:
We know that Sally picked 6 2/3 pounds of apples, which can be converted into an improper fraction: 20/3. Multiply 20/3 and 1/2. You will get 20/6, which is 3 1/3. Hope this helped :D
Answer:
Final answer is c=-7.
Step-by-step explanation:
Given equation is .
Now question says that Misha wrote the quadratic equation 0=-x2+4x-7 in standard form. Now we need to find about what is the value of c in her equation.
We know that standard form of quadratic equation is given by .
compare given equation with the standard form, we find that -7 is written in place of +c
so that means +c=-7
or c=-7
Hence final answer is c=-7.