Answer: Explanation:First, let's call the number of 2 cent coins: tNext, let's call the number of 5 cent coins: fWe can then write to equations from the information in the problem.Equation 1: t+f=40Equation 2: 0.02t+0.05f=1.55Step 1) Solve the first equation for t:t+f=40t+f−f=40−ft+0=40−ft=40−fStep 2) Substitute (40−f) for t in the second equation and solve for f:0.02t+0.05f=1.55 becomes:0.02(40−f)+0.05f=1.55(0.02×40)−(0.02×f)+0.05f=1.550.80−0.02f+0.05f=1.550.80+(−0.02+0.05)f=1.550.80+0.03f=1.550.80−0.80+0.03f=1.55−0.800+0.03f=0.750.03f=0.750.03f0.03=0.750.030.03f0.03=25f=25Step 3) Substitute 25 for f in the solution to the first equation at the end of Step 1 and calculate t:t=40−f becomes:t=40−25t=15The Solution Is:There are:15 two cent coins25 five cent coins
Step-by-step explanation:
Answer:it’s 0
Step-by-step explanation:
You do -3 plus 4 and then minus 1 which would be 0
Quadrant IV is also known as the 4th quadrant. Imagine it like a C: 1st quadrant is in the top right, 2nd quadrant is in the top left, 3rd quadrant is in the bottom left, and the 4th quadrant is in the bottom right. With this information in mind, the answer is A) P, B, K
Answer:
Die= 6 possible outcomes
spinner= 4 possible outcomes
word= 4 possible outcomes
alphabet= 26 possible outcomes
cards= 15 possible outcomes
Answer: About 6.71 units
Step-by-step explanation:
You use the distance formula: 
.
Assign the the two points to the variables:
Substitute them in the formula:
And solve it:
