I'm not completely sure but this is what I would do.
evaluate <span>(1/ 4)^x - 1 </span>as is. But change the (1 /2)^2x to (2/4)^2x. This way both fractions have the same denominator and in this sense, the same base. The 2/4 base still evaluates into 1/2 so nothing, mathematically, is being broken here.
It should be A if I did the math right which I think I did
27-48x^4= 3(9-16x^4)
Because 3 is the GCF
Answer:
-2
Step-by-step explanation:
3|x-7|<= 27
then |x-7|<=27/3=9
hence, -9<=x-7<=9
therefore, -2<=x<=16
