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3 years ago

Kaylin is tracking the progress of a plant’s growth. Today the plant is 4 cm high. The plant grows 0.5 cm per day.

1 answer:

8 0

Answer: I dont know the answer becuase this makes no sinse what are you trying to ask because all you are saying is how much it grows a day

Step-by-step explanation:

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If A = 3r^2h^2, and (rh) increases by 100%, then the new A is how many times greater than the old A? PLEASE HELP ME!!! (Specify

Maslowich

Answer: the answer is 3

Step-by-step explanation:

An increase of 100% in the value of (rh) means the value doubles. When that doubled value is squared, the new area is 4 times the old area.The question asks how many times GREATER the new A is than the old A. 4 times AS LARGE AS is a 300% INCREASE, which is 3 TIMES LARGER THAN.So the grammatically correct answer is 3

3 0

2 years ago

Math question down below

siniylev [52]

The first is equal, but the second is not. Hope this helps!

7 0

3 years ago

Calculate the sample standard deviation and sample variance for the following frequency distribution of heart rates for a sample

adelina 88 [10]

Answer:

$\sigma = 12.5$ ---- sample standard deviation

$\sigma^2 = 157.2$ ---- sample variance

Step-by-step explanation:

Solving (a): The sample variance

First, we calculate the midpoint of each class (this is the average of the limits)

So, we have:

$x_1 = \frac{56 + 64}{2} = 60$

$x_2 = \frac{65 + 73}{2} = 69$

And so on

So, the table becomes:

$\begin{array}{cc}{x} & {f} & {60} & {11} & {69} & {15} & {78} & {14} & {87} & {4} & {96} & 11 \ \end{array}$

Calculate the mean

$\bar x = \frac{\sum fx}{\sum f}$

$\bar x = \frac{60*11+69*15+78*14+87*4+96*11}{11+15+14+4+11}$

$\bar x = \frac{4191}{55}$

$\bar x = 76.2$

The variance is:

$\sigma^2 = \frac{\sum f(x - \bar x)^2}{\sum f - 1}$

So, we have:

$\sigma^2 = \frac{(60 - 76.2)^2*11+(69 - 76.2)^2*15+(78 - 76.2)^2 *14+(87 - 76.2)^2*4+(96 - 76.2)^2*11}{11+15+14+4+11-1}$

$\sigma^2 = \frac{8488.8}{54}$

$\sigma^2 = 157.2$

The sample standard deviation is:

$\sigma = \sqrt{\sigma^2$

$\sigma = \sqrt{157.2$

$\sigma = 12.5$

Solving (b): The sample variance

In (a), we calculate the sample variance to be:

$\sigma^2 = 157.2$

6 0

3 years ago

Answer this please . <br><br><br>

Monica [59]

Answer:

$\frac{3}{5}x+2=\frac{2}{3}x\\\\\frac{3}{5}x+2-2=\frac{2}{3}x-2\\\\\frac{3}{5}x=\frac{2}{3}x-2\\\\\frac{3}{5}x-\frac{2}{3}x=\frac{2}{3}x-2-\frac{2}{3}x\\\\-\frac{1}{15}x=-2\\\\\left(-\frac{1}{15}x\right)\left(-15\right)=\left(-2\right)\left(-15\right)\\\\x=30$

hope this helps you

4 0

3 years ago

Read 2 more answers

A trapezoid is quadrilateral with at least one pair of parallel sides. The quadrilateral shown is a trapezoid. If m<1 = 90* a

Lynna [10]

Well the angles should all equal 360. Since you know 90 and 160 then 360-90-160=110. Angle 2 is 90* so 110-90=20 so angle 4 is 20. Angle 2+ angle 4: 90+20=110 or C :)

7 0

3 years ago