Answer:
- x-intercepts: -3, -2, -1, 1, 2
- y-intercept: 12
- symmetry: none
Step-by-step explanation:
The x- and y-intercepts are the points where the graph crosses the x- and y-axes, respectively. If an odd-degree polynomial function has any symmetry, it will be symmetrical about the origin.
<h3>X-intercepts</h3>
The graph shows crossings of the x-axis at -3, -2, -1, 1, and 2. These are the x-intercepts. Expressed as coordinate pairs, each will have a y-coordinate of zero:
(-3, 0), (-2, 0), (-1, 0), (1, 0), (2, 0)
<h3>Y-intercepts</h3>
If the function is not vertically scaled, the y-intercept of an odd-degree function will be the opposite of the product of the x-intercepts:
-(-3)(-2)(-1)(1)(2) = 12
It will have an x-coordinate of zero:
(0, 12) . . . y-intercept
A function can have at most 1 y-intercept.
<h3>Symmetry</h3>
There are two features of this graph that tell you it is an odd-degree function:
- the end behavior is in opposite directions
- there are an odd number of x-intercepts (x-axis crossings)
An odd-degree function will only be symmetrical about the origin. This function has more negative x-intercepts than positive ones, so is not symmetrical about the origin.
The graph has no symmetry.
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<em>Additional comment</em>
Turning points without an x-axis-crossing on either side, or axis "touches" (not crossing) signify complex or even-multiplicity roots. The function will only be of odd degree if there are an odd number of x-axis crossings.
The end behavior of an odd-degree function will be in opposite directions: the infinity will match the sign of x if the leading coefficient is positive, or be opposite to the sign of x if the leading coefficient is negative.
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