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Assoli18 [71]
3 years ago
7

At what value of x does graph of the following function f(x) have a vertical asymptote? F(x)= 1/x+3

Mathematics
1 answer:
kirill115 [55]3 years ago
7 0

Answer:

A

Step-by-step explanation:

Given

f(x) = \frac{1}{x+3}

The denominator of f(x) cannot be zero as this would make f(x) undefined.

Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non zero for this value then it is a vertical asymptote.

x + 3 = 0 → x = - 3 is the vertical asymptote

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The given statement is:

41 fewer than the quantity t times 307 is equal to n.

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The Nutty Professor sells cashews for $7.10 per pound and Brazil nuts for $4.60 per pound. How much of each type should be used
aivan3 [116]

Answer:

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Step-by-step explanation:

Let c be the pounds of cashew

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From equation 2

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Sub 32-b for c in equation 1

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- 2.5b= -27.61

b= 27.61/2.5

b= 11.04

Sub 11.04 for b in equation 2

c+b= 32

c + 11.04= 32

c= 32-11.04

c= 20.96

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Step-by-step explanation:

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Step-by-step explanation:

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