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3 years ago

At what value of x does graph of the following function f(x) have a vertical asymptote? F(x)= 1/x+3

Mathematics

1 answer:

kirill115 [55]3 years ago

7 0

Answer:

Step-by-step explanation:

Given

f(x) = $\frac{1}{x+3}$

The denominator of f(x) cannot be zero as this would make f(x) undefined.

Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non zero for this value then it is a vertical asymptote.

x + 3 = 0 → x = - 3 is the vertical asymptote

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