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Assoli18 [71]
3 years ago
7

At what value of x does graph of the following function f(x) have a vertical asymptote? F(x)= 1/x+3

Mathematics
1 answer:
kirill115 [55]3 years ago
7 0

Answer:

A

Step-by-step explanation:

Given

f(x) = \frac{1}{x+3}

The denominator of f(x) cannot be zero as this would make f(x) undefined.

Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non zero for this value then it is a vertical asymptote.

x + 3 = 0 → x = - 3 is the vertical asymptote

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Let f(x) = 1/x . Find the number b such that the average rate of change of f on the interval [2, b] is − 1/8
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So, we have the function f(x)=1/x. We need to find b such that the average rate of change or the slope is -1/8 between the intervel [2, b]. First, let's find f(2).

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