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3 years ago

A total distance greater than 10 kilometers and less than or equal to 30 kilometers

Mathematics

2 answers:

Vikki [24]3 years ago

8 0

Answer:

345x

Step-by-step explanation:

6274y

denis-greek [22]3 years ago

4 0

Answer:

10 < x < or = 30

Step-by-step explanation:

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4. Order the set of numbers from least to greatest: 164.8. 814 7 (5 points) 2 o 15 V64 88.14 V64.8 81 2 3. 814 64 o V64 . 3. 814

kirza4 [7]

Answer:

For the answer to the question above,

the Order the set of numbers from least to greatest: square root 64, 8 and 1 over 7, 8.14 repeating 14, 15 over 2

15 over 2, square root 64, 8 1 over 7, 8.14 repeating 14.

Step-by-step explanation:

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3 years ago

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What is the zero of the following function, f(x) = –(2/7) x − 10?

Stels [109]

Answer:

Step-by-step explanation:

the zeros of a function f are found by solving the equation f(x) = 0. Example 1. Find the zero of the linear function f is given by. f(x) = -2 x + 4 I hope this helps.

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3 years ago

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prohojiy [21]

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2 years ago

Suppose a scientist has 13 liters of acid and she needs 16 liters for an experiment.

vekshin1

B cause 13 plus x is equal to the 16 liters that u need and u already have 13 liters

3 0

2 years ago

Suppose the weights of the Boxers at this club are Normally distributed with a mean of 166 pounds and a standard deviation of 5.

lesya [120]

Answer:

0.1994 is the required probability.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 166 pounds

Standard Deviation, σ = 5.3 pounds

Sample size, n = 20

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

Standard error due to sampling =

$=\dfrac{\sigma}{\sqrt{n}} = \dfrac{5.3}{\sqrt{20}} = 1.1851$

P(sample of 20 boxers is more than 167 pounds)

$P( x > 167) = P( z > \displaystyle\frac{167 - 166}{1.1851}) = P(z > 0.8438)$

$= 1 - P(z \leq 0.8438)$

Calculation the value from standard normal z table, we have,

$P(x > 167) = 1 - 0.8006= 0.1994 = 19.94\%$

0.1994 is the probability that the mean weight of a random sample of 20 boxers is more than 167 pounds

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2 years ago