The answer to the problem is as follows:
x = sin(t/2)
<span>y = cos(t/2) </span>
<span>Square both equations and add to eliminate the parameter t: </span>
<span>x^2 + y^2 = sin^2(t/2) + cos^2(t/2) = 1 </span>
<span>The final step is translating the original parameter limits into limits on x and y. Over the -Pi to +Pi range of t, x varies from -1 to +1, whereas y varies from 0 to 1. Thus we have the semicircle in quadrants I and II: y >= 0.</span>
Answer:
The equation is not linear
Step-by-step explanation:
You are given the equation

Express y in terms of x:

The linear function must of form

where m and b are real numbers.
Your function is not of this form, so this is not a linear function.
Answer:
line a and b are parallel
line c is not perpendicular because it is not 3
step-by-step explanation:
if the slope is the same it is parallel
if the slope is the complete opposite it is perpendicular
lines a and b are parallel with a slope of -1/3
(0, 5) (3, 4)
m = 4 - 5 / 3 - 0
m = -1 / 3
m = -1/3
(-1, 1) (2, 0)
m = 0 - 1 / 2 + 1
m = -1 / 3
m = -1/3
line c is perpendicular to lines a and b the slope is
(0, 0) (2, 5)
m = 5 - 0 / 2 - 0
m = 5/2
2.5
Answer:
I think its 2 but Idk how to show work sorry
Step-by-step explanation:
Answer:
24.84
Step-by-step explanation:
use Pythagoras theorem
h=√p²+b² = √(19)²+(16)² = √617 =24.84